Answer:
a = 2, r = 5
Step-by-step explanation:
Nth term of a GP = a×r^(n-1)
Where 'a' is the first term and 'r' is the common ratio
4th term = a×r^3 = 250
r^3 = 250/a
7th term = a×r^6 = 31250
a×r^6 = 31250
a×(r^3)^2 = 31250
a×(250/a)^2 = 31250
a×(62500/a^2) = 31250
62500/a = 31250
a = 62500/31250 = 2
a = 2
since r^3 = 250/a,
r^3 = 250/2 = 125
r = (125)^(1/3)
r = 5
Answer:
(-3 , 0) (0, 2) (6, -6)
Step-by-step explanation:
Solving for x - intercept:
2x - 3(0) = -6
2x = -6
2x/2 = -6/2
x = -3
One point would be (-3 , 0) .
Solving for y-intercept:
2(0) - 3y = -6
-3y = -6
-3y/-3 = -6/-3
y = 2
Another point would be (0, 2).
When 'x' equals 6:
2(6) - 3y = -6
12 - 3y = -6
12 - 12 - 3y = -6 - 12
-3y = -18
-3y/3 = -18/3
y = -6
The third point would be (6, -6).
A quadratic equation is one in which the highest exponent of x is 2.
is quadratic; the highest exponent is 2.
x³-3x²+1=0 is NOT quadratic. The highest exponent of x is 3, not 2.
5x-7=0 is NOT quadratic. The highest exponent of x is 1, not 2.
x²+3x-5=0 is quadratic; the highest exponent of x is 2.
x-5=9x+7 is NOT quadratic. The highest exponent of x is 1, not 2.
x²-x=3x+7 is quadratic; the highest exponent of x is 2.
Answer:
y- intercept --> Location on graph where input is zero
f(x) < 0 --> Intervals of the domain where the graph is below the x-axis
x- intercept --> Location on graph where output is zero
f(x) > 0 --> Intervals of the domain where the graph is above the x-axis
Step-by-step explanation:
Y-intercept: The y-intercept is equivalent to the point where x= 0. 'x' is the input variable in an equation, therefore the y-intercept is where the input, or x, is equal to 0.
f(x) <0: Notice the 'lesser than' sign. This means that the value of f(x), or 'y', is less than 0. This means that this area consists of intervals of the domain below the x-axis.
X-intercept: The x-intercept is the location of the graph where y= 0, or the output is equal to 0.
f(x) >0: In this, there is a 'greater than' sign. This means that f(x), or 'y', is greater than 0. Therefore, this consists of intervals of the domain above the x-axis.
Step-by-step explanation
The orange machine, the very end of the shovel part. That line is a slope. The middle part of the scooper could also be a slope. The very beginng part of the scooper is also a slope. The bottom part of the scooper is also a slope. The bottom part at the end of the scooper could also be slope.
