Answer:
6 possible integers
Step-by-step explanation:
Given
A decreasing geometric sequence

Required
Determine the possible integer values of m
Assume the first term of the sequence to be positive integer x;
The next sequence will be 
The next will be; 
The nth term will be 
For each of the successive terms to be less than the previous term;
then
must be a proper fraction;
This implies that:

<em>Where 7 is the denominator</em>
<em>The sets of </em>
<em> is </em>
<em> and their are 6 items in this set</em>
<em>Hence, there are 6 possible integer</em>
Answer:
y=5x+25
y=5(12)+25
y=85
Step-by-step explanation:
Answer:
-2y
Step-by-step explanation:
Let's simplify step-by-step.
x−y−(x+y)
Distribute the Negative Sign:
=x−y+−1(x+y)
=x+−y+−1x+−1y
=x+−y+−x+−y
Combine Like Terms:
=x+−y+−x+−y
=(x+−x)+(−y+−y)
=−2y
I BELIEVE THAT ALL (96m^3) IS UNDER THE SQUARE ROOT.
If so : 96 could be written as 16x 6 & m³ could be written as m²xm:
7√(96m^3) = 7√(16 x 6 x m² m) =7[4m√(6m)]
=28m√(6m)