I think z is ether 8 or -3. hope this helps <span />
I think that the answer is -1/6. I got this by subtracting 3 on both sides according to the order of operations and got -1. Next, I divided 6 on both sides to undo the multiplication. Since you can't do 1 divided by 6, you can leave it as a fraction which is -1/6.
Answer:
Set builder notation: {a | a ≥ -21}
Interval notation: [-21, ∞)
Step-by-step explanation:
A set represents a collection of things, objects, or numbers. A set builder notation is in the form y = {x | x is an odd number between 8 and 10}, which means y contains all the odd numbers between 8 and 10.
Interval notation is a way to define a set of numbers between a lower limit and an upper limit using end-point values. for example (8, 20) means numbers between 8 and 20.
Given -3a-15≤-2a+6; solving :
-3a - 15 ≤ -2a + 6
-3a + 2a ≤ 6 + 15
-a ≤ 21
dividing through by -1:
a ≥ -21
The solution is:
Set builder notation: {a | a ≥ -21}
Interval notation: [-21, ∞)
R=1v+h([pi]h^2) all over 3
Answer:
50% decrease
Step-by-step explanation:
