f(x) = tan2(x) + (√3 - 1)[tan(x)] - √3 = 0
tan2(x) + √3[tan(x)] - tan(x) - √3 = 0
Factor into
[-1 + tan(x)]*[√3 + tan(x)] = 0
which means
[-1 + tan(x)] = 0 and/or [√3 + tan(x)] = 0
Then
tan(x) = 1
tan-1(1) = pi/4 radians
For the other equation
[√3 + tan(x)] = 0
tan(x) = -√3
tan-1(-√3) = -pi/3
so that
x = pi/4 or -pi/3 in the interval [0, 2pi]
Answer:
x=4
Step-by-step explanation:
We can use the leg rule
hyp leg
------- = -----------------
leg part
2+6 x
------- = -----------------
x 2
Using cross products
8*2 = x^2
16 =x^2
Take the square root of each side
4 =x
-3=7x -10
-7x=-10+3
-7x=-7
x=1
