T = days passed
r = rate of growth
by 0 day, or t = 0, there are 2 folks sick,
by the third day, t = 3, there are 40 folks sick,
![\bf \qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\to &40\\ P=\textit{initial amount}\to &2\\ r=rate\to r\%\to \frac{r}{100}\\ t=\textit{elapsed time}\to &3\\ \end{cases} \\\\\\ 40=2(1+r)^3\implies 20=(1+r)^3\implies \sqrt[3]{20}=1+r \\\\\\ \sqrt[3]{20}-1=r\implies 1.7\approx r\qquad \boxed{A=2(2.7)^t}](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Ctextit%7BAmount%20for%20Exponential%20Growth%7D%0A%5C%5C%5C%5C%0AA%3DP%281%20%2B%20r%29%5Et%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0AA%3D%5Ctextit%7Baccumulated%20amount%7D%5Cto%20%2640%5C%5C%0AP%3D%5Ctextit%7Binitial%20amount%7D%5Cto%20%262%5C%5C%0Ar%3Drate%5Cto%20r%5C%25%5Cto%20%5Cfrac%7Br%7D%7B100%7D%5C%5C%0At%3D%5Ctextit%7Belapsed%20time%7D%5Cto%20%263%5C%5C%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0A40%3D2%281%2Br%29%5E3%5Cimplies%2020%3D%281%2Br%29%5E3%5Cimplies%20%5Csqrt%5B3%5D%7B20%7D%3D1%2Br%0A%5C%5C%5C%5C%5C%5C%0A%5Csqrt%5B3%5D%7B20%7D-1%3Dr%5Cimplies%201.7%5Capprox%20r%5Cqquad%20%5Cboxed%7BA%3D2%282.7%29%5Et%7D)
how many folks are there sick by t = 6?
You would have to set you problem up like
x 40
____=_____
720 100
you would multiply 40 by 720 then you would divide 28,800 by 100 your answer will be 288.
Answer:
p = 6; RPQ = 60 degrees
Step-by-step explanation:
Because RPS is 120 degrees and it is bisected by PQ (cut into 2 equal parts), we can determine that both sides are 60 degrees. Set the expression 5p+30 equal to 60 to find the value of p.
5p + 30 = 60
5p = 30
p = 6
So now you have determined that p = 6, and the measure of RPQ is 60 degrees.
Hope this helped!
Answer:
s = 33
Step-by-step explanation:
99=3s
(99/3) = s
s=33
Answer:
h = 12x^5y^3
Step-by-step explanation:
The area of a parallelogram is found using A = b*h. Substitute the values given and solve for h.
A = b*h
36x^6 y^5 = 3xy^2 * h
36x^6 y^5 ÷ 3xy^2 = h
12x^5y^3 = h
