<u>The correct answer is 580.
</u>The upward force the right tension cord exerts on the traffic light is equal to about 114.35 N. Because the stoplight is being help upright the natural force (upward force) provided by both tension cords must be equal to the gravitational (downward) force of the traffic light which is 331.
If 114 is the upward force on the right side then 216 N must be the force provided by the left side.
You then have a right triangle with the length opposite theta = about 216 and theta = 22. So sin(22)* X = 216, where X is the length of the hypotenuse, or the force found in the left cord.
with sig figs added to the mix the answer is 580 N
I believe the answer is true to the E dgenuity physics course
2. 0 mc charge in an external field of 20n/c, north (direction) will experience a force of 0.4 newtons, the direction of the force is north
Force in an electric field = charge * electric field
given
charge = 2*
C
electric field = 20 N/C
Force in an electric field = 2*
* 20
= 0.04 N
since , external field is in north direction then the force must be in north direction because the direction of an electric field at a point is the same as the direction of the electric force acting on a positive test charge
hence, 2. 0 mc charge in an external field of 20n/c, north (direction) will experience a force of 0.4 newtons, the direction of the force is north
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Answer:
should be tested by the scientific community
Overweight:25 to 30, obese: over 30