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Bad White [126]
3 years ago
9

What is the minimum body mass index for obesity

Physics
2 answers:
solong [7]3 years ago
4 0

Answer:

30.1

Explanation:

The BMI classify people in underweight, normal weight, overweight and obesity, based exclusively on the individual's mass and height. The following classification are commonly accepted: underweight below 18.5 \frac{kg}{m^2}, normal weight: 18.5 to 25, overweight: 25 to 30 , obese: more than 30.

Tju [1.3M]3 years ago
3 0
Overweight:25 to 30, obese: over 30
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If a net force acting on a moving object causes its speed to increase, what
Klio2033 [76]

Answer:

It increases.

Explanation:

If a force acts in the same direction as the object's motion, then the force speeds the object up. Either way, a force will change the velocity of an object. And if the velocity of the object is changed, then the momentum of the object is changed.

7 0
3 years ago
A force is applied to a 2.8 kg mass and produces 3.9 m/s 2 acceleration. what acceleration would be produced by the same force a
OverLord2011 [107]
Force applied on first mass = 2.8×3.9 = 10.92N
same force = 8.2×a
therefore
a = 10.92÷8.2 = 1.33ms-²
3 0
4 years ago
You wish to lift a 12,000 lb stone by a vertical distance of 15 ft. Unfortunately, you can only generate a maximum pushing force
DochEvi [55]

Answer:

5,760,000 lb-ft²/s²

Explanation:

Work done, W = mgy where m = mass of stone = 12,000 lb, g = 32 ft/s² and y = vertical distance = 15 ft.

So, W = mgy = 12,000 lb × 32 ft/s² × 15 ft. = 5,760,000 lb-ft²/s²

6 0
3 years ago
A machine part has the shape of a solid uniform sphere of mass 250 g and a diameter of 4.30 cm. It is spinning about a frictionl
zysi [14]

Answer:\alpha =9.302\ rad/s^2

Explanation:

Given

mass of sphere m=250\ gm

diameter of sphere d=4.30\ cm

radius r=\frac{4.30}{2}\ cm

f=0.0200\ N

friction will provide resisting torque so

f\times r=I\times \alpha

where I=\text{moment of Inertia}

f=\text{friction force}

\alpha =\text{angular acceleration}

I=\frac{2}{5}mr^2

0.02\times r=\frac{2}{5}mr^2\times \alpha

\alpha =\frac{5}{2r}\times f

\alpha =\frac{5}{2}\times \frac{2}{4.3\times 10^{-2}}\times 0.02

\alpha =9.302\ rad/s^2

(b)time taken to decrease its rotational speed by 21\ rad/s

t=\dfrac{\Delta \omega }{\alpha }

t=\dfrac{21}{9.302}

t=2.25\ s

6 0
3 years ago
a boy standing by a lake sees a fish in the pond and tries to thrust a spear into it he will success or not​
almond37 [142]

Answer:

yes

Explanation:

8 0
3 years ago
Read 2 more answers
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