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uysha [10]
3 years ago
9

If the needle in the galvanometer is going up, what can you conclude about the motion of the magnet in the diagram?

Physics
2 answers:
Jet001 [13]3 years ago
4 0

Answer:

t is not moving.

It must be moving left.

It must be moving right.

It is being moved in an unknown direction

Answer is: It must be moving right

Explanation:

Papessa [141]3 years ago
4 0

I just took the test, the correct answer is "It must be moving left."

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A 12,500 N alien UFO is hovering about the surface of Earth. At time , its position can be given as () = ((0.24 m/s^3)^3 + 25 m)
stepladder [879]

a) F=(3675i-4543k)N

b) 5843 N

Explanation:

a)

The position of the UFO at time t is given by the vector:

r(t)=(0.24t^3+25)i+(4.2t)j+(-0.43t^3+0.8t^2)k

Therefore it has 3 components:

r_x=0.24t^3+25\\r_y=4.2t\\r_z=-0.43t^3+0.8t^2

We start by finding the velocity of the UFO, which is given by the derivative of the position:

v_x=r'_x=\frac{d}{dt}(0.24t^3+25)=3\cdot 0.24t^2=0.72t^2\\v_y=r'_y=\frac{d}{dt}(4.2t)=4.2\\v_x=r'_z=\frac{d}{dt}(-0.43t^3+0.8t^2)=-1.29t^2+1.6t

And then, by differentiating again, we find the acceleration:

a_x=v'_x=\frac{d}{dt}(0.72t^2)=1.44t\\a_y=v'_y=\frac{d}{dt}(4.2)=0\\a_z=v'_z=\frac{d}{dt}(-1.29t^2+1.6t)=-2.58t+1.6

The weight of the UFO is W = 12,500 N, so its mass is:

m=\frac{W}{g}=\frac{12500}{9.8}=1276 kg

Therefore, the components of the force on the UFO are given by Newton's second law:

F=ma

So, Substituting t = 2 s, we find:

F_x=ma_x=(1276)(1.44t)=(1276)(1.44)(2)=3675 N\\F_y=ma_y=0\\F_z=ma_z=(1276)(-2.58t+1.6)=(1276)(-2.58(2)+1.6)=-4543 N

So the net force on the UFO at t = 2 s is

F=(3675i-4543k)N

b)

The magnitude of a 3-dimensional vector is given by

|v|=\sqrt{v_x^2+v_y^2+v_z^2}

where

v_x,v_y,v_z are the three components of the vector

In this problem, the three components of the net force are:

F_x=3675 N\\F_y=0\\F_z=-4543 N

Therefore, substituting into the equation, we find the magnitude of the net force:

|F|=\sqrt{3675^2+0^2+(-4543)^2}=5843 N

7 0
3 years ago
The density of lead is 11.3 g/cm 3. What mass of lead is required to make a 1 cm 3 fishing sinker?
Aliun [14]

Answer:

11.3 g

Explanation:

given,

density of the lead = 11.3 g/cm³

volume = 1 cm³

mass of the lead = ?

we know,

density=\dfrac{mass}{volume}

mass = volume x density

mass = 1 x 11.3

mass = 11.3 g

hence, the mass of the lead is equal to 11.3 g

5 0
3 years ago
Read 2 more answers
Define compound and list two examples.
Liono4ka [1.6K]
A compound is a substance that consists of two or more elements, which is chemically combined, meaning that it could only be split by chemical means. 

Examples:-

- NaCl is salt, chemically combined of Sodium and Chloride. 

- H2O is water, chemically combined of Hydrogen and oxygen. 
8 0
3 years ago
Read 2 more answers
If a resultant vector is 12 m/s and the horizontal component is 9 m/s, what is the value of the vertical component? A. 5.8 m/s B
horrorfan [7]

The vertical component is B) 7.9 m/s

Explanation:

A vector can be resolved into its horizontal and vertical components. The horizontal and the vertical components form the sides of a right triangle, in which the resultant corresponds to the hypothenuse, so we can use Pythagorean's theorem:

R=\sqrt{R_x^2+R_y^2}

where

R is the resultant vector

Rx is the horizontal component

Ry is the vertical component

In this problem, we have:

R = 12 m/s is the resultant vector

Rx = 9 m/s is the horizontal component

Solving the formula for Ry, we find the vertical component:

R_y = \sqrt{R^2-R_x^2}=\sqrt{12^2-9^2}=7.9 m/s

Learn more about vector components:

brainly.com/question/2678571

#LearnwithBrainly

3 0
3 years ago
What are the strengths and limitations of the doppler and transit methods? What kind of planets are easiest to detect with each
Arturiano [62]

\huge\mathfrak\red{✔Answer:-}

Strength: able to detect planets in a wide range of orbits, as long as orbits aren't face on

Limitations: yield only planet's mass and orbital properties

3 0
4 years ago
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