This problem can be solved by Dalton's law of partial pressures which states that <em>in a mixture of non-reacting gases, the total pressure exerted is equal to the sum of the partial pressures of the individual gases</em>.
Ptotal = P₁ + P₂ + P₃ + ..... + Pn
Herein, Ptotal = P(Ne) + P(Ar) + P(He)
Ptotal = 1.25 atm, P(Ne) = 0.68 atm and P(Ar) = 0.35
So, P(He) = Ptotal - P(Ne) - P(Ar) = 1.25 - 0.68 - 0.35 = 0.22 atm
Answer:
Your answer is C
Explanation:
When an acid and base react, the acidic hydrogen ion and the basic hydroxide ion in each acid and base neutralize each other and form water. Meanwhile the conjugate base and conjugate acid (the leftover compounds) react to form an ionic molecule, or a salt. (In chemistry, when an anion and a cation form an ionic bond the new molecule is called a salt). Hope this helps!
Answer:
1200 mL
Explanation:
Given data
- Initial pressure (P₁): 600.0 mmHg
- Initial volume (V₁): 400.0 mL
- Final pressure (P₂): 200.0 mmHg
For a gaseous sample, there is an inverse relationship between the pressure and the volume. If we consider the gas as an ideal gas, we can find the final volume using Boyle's law.
![P_1 \times V_1 = P_2 \times V_2\\V_2 = \frac{P_1 \times V_1}{P_2} = \frac{600.0mmHg \times 400.0mL}{200.0mmHg}=1200 mL](https://tex.z-dn.net/?f=P_1%20%5Ctimes%20V_1%20%3D%20P_2%20%5Ctimes%20V_2%5C%5CV_2%20%3D%20%5Cfrac%7BP_1%20%5Ctimes%20V_1%7D%7BP_2%7D%20%3D%20%5Cfrac%7B600.0mmHg%20%5Ctimes%20400.0mL%7D%7B200.0mmHg%7D%3D1200%20mL)