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andriy [413]
2 years ago
13

Adriana is planning to ride the public bus to and from school this year. She wants to figure out how much it will cost her. The

bus ride costs $1.25` each direction.
Let C represent the total cost of Adriana's bus rides and let r represent how many times Adriana rides the bus in one direction. Identify a quantity to be the independent variable and one to be the dependent variable for this situation.

I WILL MARK BRAINLIEST
Mathematics
1 answer:
lutik1710 [3]2 years ago
4 0

Answer:

C is the dependent variable and r is independent

Step-by-step explanation:

Adriana can ride the bus any number of times she wants. No one is stopping her from doing that so 'r' becomes an independent quantity.

Whereas, the total cost for the bus rides depends on the number of times Adriana rides the bus and the relation is given as, C=1.25r

This is because it costs $1.25 each time she rides the bus in one direction

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Step-by-step explanation:

Confidence Interval for the population proportion is basically an interval of range of values where the true population proportion can be found with a certain level of confidence.

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Confidence Interval = (Sample proportion) ± (Margin of error)

Sample proportion = proportion of Americans in the sample that would give themselves grade of A or B on their financial knowledge of personal finance = p = (934/1663) = 0.56

Margin of Error is the width of the confidence interval about the mean.

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Margin of Error = (Critical value) × (standard Error)

Critical value at 95% confidence interval for sample size of 1663 is obtained from the z-tables as the sample size is large enough for the sample properties to approximate the population properties.

Critical value = 1.960 (from the z-tables)

Standard error of the mean = σₓ = √[p(1-p)/n]

p = 0.56

n = sample size = 1663

σₓ = √[0.56×0.44/1663] = 0.0121723457 = 0.01217

95% Confidence Interval = (Sample proportion) ± [(Critical value) × (standard Error)]

CI = 0.56 ± (1.96 × 0.01217)

CI = 0.56 ± 0.0238532

95% CI = (0.5361468, 0.5838532)

95% Confidence interval = (0.536, 0.584)

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