An object is launched at 39.2 meters per second (m/s) from a 42.3-meter tall platform. The equation for the object's height s at
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Answer:
((4,19), (\frac{-3}{4},0), (-6,-21))
Step-by-step explanation:
We have the linear equation given by, y = 4x + 3.
So, for the ordered pairs, we will substitute the given co-ordinate in the equation to find the other co-ordinate.
1. We are given, x = 4.
So, y = 4x + 3 ⇒ y = 4 × 4 + 3 ⇒ y = 16 + 3 ⇒ y = 19.
Hence, the ordered pair is (4,19).
2. It is given that y = 0.
So, y = 4x + 3 ⇒ 0 = 4x + 3 ⇒ 4x = -3 ⇒
Thus, the ordered pair is (\frac{-3}{4},0).
3. We have, y = -21
So, y = 4x + 3 ⇒ -21 = 4x + 3 ⇒ 4x = -21-3 ⇒ 4x = -24 ⇒ x = -6.
So, the ordered pair is (-6,-21).
Hence, we get that the ordered pairs are ((4,19), (\frac{-3}{4},0), (-6,-21)).