Finding the vertex of the parabola
<span>y = (x + 5)^2 + 8 the vertex is at (-5, 8)
its coefficient so the parabola turns upward so the range is [8 , inf]</span>
Answer:
(2, 2 )
Step-by-step explanation:
Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is
[
(x₁ + x₂ ) ,
(y₁ + y₂ ) ]
Here (x₁, y₁ ) = (A(5, 8) and (x₂, y₂ ) = B(- 1, - 4) , thus
midpoint = [
(5 - 1),
(8 - 4 ) ] = (2, 2 )
Total = Principal * (1 + rate)^years
Total = 1,300 * (1.0475) ^ 5
Total = 1,300 *
<span>
<span>
<span>
1.2611599139
</span>
</span>
</span>
Total =
<span>
<span>
<span>
1,639.5</span></span></span>1
AB = 24
BC = 45
AC = 51
cos C = adjacent / hypotenuse
cos C = BC / AC
cos C = 45/51