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garri49 [273]
3 years ago
14

Solve this inequality 5p > -30

Mathematics
2 answers:
Rina8888 [55]3 years ago
6 0
5p \ \textgreater \  -30 \\ \\ p \ \textgreater \  - \frac{30}{5} \\ \\ p \ \textgreater \  -6 \\ \\

The final result is: p > -6.
yan [13]3 years ago
6 0
Divide each side by 5
p>-6

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Which line shows theINITIAL error in volume work?
aliina [53]

In step 2, V = \frac{4}{3}(3.14)(37.5) show the error in volume work.

Solution:

Given data:

The steps shows it is sphere.

Radius of the sphere = 12.5

The value of π = 3.14

Volume of the sphere = \frac{4}{3} \pi r^3

Step 1:

$V=\frac{4}{3} (3.14)(12.5)^3

$V=\frac{4}{3} (3.14)(12.5)(12.5)(12.5)

Step 2:

$V=\frac{4}{3} (3.14)(1953.125)

Step 3:

$V=\frac{4}{3} (6132.81)

Step 4:

V = 8177.08 cubic units

This is the correct solution.

But in the given options, in step 2, 12.5 is multiplied by 3.

That is not the correct step. You have to do 12.5 × 12.5 × 12.5.

Hence in step 2, V = \frac{4}{3}(3.14)(37.5) show the error in volume work.

7 0
3 years ago
What point names the ordered pair (3, -5)?
gregori [183]

Answer:

D

Step-by-step explanation:

We start at the origin (we the axis cross)

We go three units to the right, then 5 units down.

We end up at  the point D

5 0
3 years ago
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Someone 1v1 me on Fortnite im a na west competitive player on pc 144 hz my epic is TNA Rims add me and ill win boxfight
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Answer:

K

Step-by-step explanation:

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3 years ago
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A line passes through point A(10,15). A second point on the line has an x-value that is 125% of the x-value of point A and a y-v
melisa1 [442]

The equation of the line in the point-slope form is y - 15 = -\frac{3}{2} (x - 10)

Step-by-step explanation:

The point-slope form of a linear equation is y-y_{1}=m(x-x_{1}) , where

  • m is the slope of the line, where m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} , (x_{1},y_{1}) and (x_{2},y_{2}) are two points on the line
  • (x_{1},y_{1}) is a point on the line

∵ Point A = (10 , 15)

∵ The x-coordinate of the second point is 125% of x-coordinate

  of point A

∴ x-coordinate of second point = \frac{125}{100} × 10

∴ x-coordinate of second point = 12.5

∵ The y-coordinate of the second point is 75% of y-coordinate

  of point A

∴ y-coordinate of second point = \frac{75}{100} × 15

∴ y-coordinate of second point = 11.25

∴ The coordinates of the second point are (12.5 , 11.25)

Let us find the slope of the line by using the rule of it above

∵ (x_{1},y_{1}) = (10 , 15)

∵ (x_{2},y_{2}) = (12.5 , 11.25)

∴ m=\frac{11.25-15}{12.5-10}=\frac{-3.75}{2.5}=-\frac{3}{2}

Now we can write the equation

∵ The point-slope form is y-y_{1}=m(x-x_{1})

∵ m=-\frac{3}{2}

∵ (x_{1},y_{1}) = (10 , 15)

- Substitute these values in the form of the equation

∴ y - 15 = -\frac{3}{2} (x - 10)

The equation of the line in the point-slope form is y - 15 = -\frac{3}{2} (x - 10)

Learn more:

You can learn more about the linear equation in brainly.com/question/4152194

#LearnwithBrainly

5 0
3 years ago
The power generated by an electrical circuit (in watts) as a function of its current c (in amperes) is modeled by: P(c) = -12c^2
Ksenya-84 [330]

Answer:

The maximum power generated by the circuit is 300 watts.

Step-by-step explanation:

A quadratic function is one that can be written as an equation of the form:

f (x) = ax² + bx + c

where a, b and c (called terms) are any real numbers and a is nonzero.

In this case, f(x) is P(c) [the power generated], x is the current c (in amperes), a = -12, b = 120 and c = 0.

The vertex is a point that is part of the parabola, which has the value as ordered  minimum or maximum function. If the scalar a> 0, the parabola opens or faces up and the vertex is the minimum of the function. In contrast, if a <0, the parabola opens downward and the vertex is the maximum of the function.

The calculation of the vertex, which in this case will be the maximum of the function, is carried out as follows:

  • The value of x, in this case the value of current c in amperes, can be calculated with the formula c=\frac{-b}{2*a} . In this case: c=\frac{-120}{2*(-12)} So c= 5 amperes. The current is 5 amperes.
  • The value of y, in this case the value of the electric current in watts, is obtained by substituting the value of c previously obtained in the function. In this case: P(5)= -12*5²+120*5. So P(5)= 300 watts

<u><em>The maximum power generated by the circuit is 300 watts.</em></u>

7 0
3 years ago
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