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garri49 [273]
3 years ago
14

Solve this inequality 5p > -30

Mathematics
2 answers:
Rina8888 [55]3 years ago
6 0
5p \ \textgreater \  -30 \\ \\ p \ \textgreater \  - \frac{30}{5} \\ \\ p \ \textgreater \  -6 \\ \\

The final result is: p > -6.
yan [13]3 years ago
6 0
Divide each side by 5
p>-6

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30 ounces = ____lb ____oz
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The answer is C. 1 lb 14 oz.
7 0
3 years ago
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(cotx+cscx)/(sinx+tanx)
Butoxors [25]

Answer:   \bold{\dfrac{cot(x)}{sin(x)}}

<u>Step-by-step explanation:</u>

Convert everything to "sin" and "cos" and then cancel out the common factors.

\dfrac{cot(x)+csc(x)}{sin(x)+tan(x)}\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)}{1}+\dfrac{sin(x)}{cos(x)}\bigg)\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg[\dfrac{sin(x)}{1}\bigg(\dfrac{cos(x)}{cos(x)}\bigg)+\dfrac{sin(x)}{cos(x)}\bigg]\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)}{cos(x)}+\dfrac{sin(x)}{cos(x)}\bigg)

\text{Simplify:}\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)+sin(x)}{cos(x)}\bigg)\\\\\\\text{Multiply by the reciprocal (fraction rules)}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)cos(x)+sin(x)}\bigg)\\\\\\\text{Factor out the common term on the right side denominator}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)(cos(x)+1)}\bigg)

\text{Cross out the common factor of (cos(x) + 1) from the top and bottom}:\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)}\bigg)\\\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times cot(x)}\qquad \rightarrow \qquad \dfrac{cot(x)}{sin(x)}

6 0
3 years ago
What linear function can be represented by the set of ordered pairs?
Kryger [21]
Y = 3x - 7

just find the slope then use two point and point slope form to solve for slope intercept form
8 0
2 years ago
PLEASE HELP THANK YOU
finlep [7]

Answer:

-4 <n <= 5

Step-by-step explanation:

Open at -4 and closed at 5 on number line so the inequality should be

-4 <n <= 5

3 0
3 years ago
In a right angle,the altitude to a 6ft hypotenuse.Find the length of the altitude and each leg.
Nuetrik [128]

Answer:a=3.6 and b=4.8

Step-by-step explanation:(a^2)+(b^2)=(c^2)

Where c is hypotenuse is equal to 6. A right triangle is also known as a 3,4,5 triangle where the 2 legs are 3 and 4 and hypotenuse is 5. Find the factor in size difference by dividing your hypotenuse of 6 by the hypotenuse of 5 you get 1.2. Now multiply the 3 and 4 by 1 2 to get your answers of 3.6 and 4.8.

To check work simply plug in your legs as a and b

(3.6^2)+(4.8^2)=(6^2)

(12.96)+(23.04)=(36)

6 0
3 years ago
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