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2 years ago

15

I would like to know the cost of c

1 answer:

Evgen [1.6K]2 years ago

8 0

Answer:

1..75c

Step-by-step explanation:

You might be interested in

Use chain rule to find dw/dt w=ln(x^2 + y^2 + z^2)^(1/2) , x=sint, y=cost, z=tant

son4ous [18]

The chain rule states that

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}$

Since $\ln(x^2+y^2+z^2)^{1/2}=\dfrac12\ln(x^2+y^2+z^2)$ , you have

$\dfrac{\partial w}{\partial x}=\dfrac x{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial x}=\dfrac y{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial z}=\dfrac z{x^2+y^2+z^2}$

and

$\dfrac{\mathrm dx}{\mathrm dt}=\cos t$
$\dfrac{\mathrm dy}{\mathrm dt}=-\sin t$
$\dfrac{\mathrm dz}{\mathrm dt}=\sec^2t$

Also, since $x^2+y^2+z^2=\sin^2t+\cos^2t+\tan^2t=1+\tan^2t=\sec^2t$ , the derivative is

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\sin t\cos t}{\sec^2t}-\dfrac{\sin t\cos t}{\sec^2t}+\dfrac{\tan t\sec^2t}{\sec^2t}$
$\dfrac{\mathrm dw}{\mathrm dt}=\tan t$

4 0

3 years ago

Bobby catches 8 passes in 3 football games. At this rate how many passes dose he catch in 15 games?expine

stepan [7]

Answer: 40

Step-by-step explanation:

I can see the answer is 40, but let's try to figure out how to do it.

I like to use the rule of 3. Let's put the number of passes on the left side and the number of games on the right side.

$\frac{8}{x}=\frac{3}{15}$

''x'' represents the number of passes in 15 games.

Solve for x;

$x=\frac{15*8}{3}\\ x=\frac{120}{3}\\ x=40$

8 0

3 years ago

The 173 workers at a factory together produce 21, 452 items per day. What is the daily rate of items per worker?

mafiozo [28]

Answer:

124 items per worker per day

Step-by-step explanation:

21,452/173=124

6 0

2 years ago

A rectangle has a perimeter of 182 in and length of 52 in. What is the width?

Alik [6]

Check the picture below.

7 0

3 years ago

Which of the following values are in the range of the function graphed below?

Dafna1 [17]

Answer:

A. 1

Step-by-step explanation:

I see only one red function line in the graph. this line represents the simple function y = 1, for x in the interval [-2,1].

the domain of a function defines the possible values for x, and the range of a function defined the possible values for y.

this function has only one possible value for y : 1

so, only A applies.

5 0

3 years ago