Write the sum of 8x^2 - x + 4 and x - 5 Show all work

Mathematics

1 answer:

tigry1 [53]2 years ago

3 0

okey

you needed the sum or division?

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Find the value of x..........

Leviafan [203]

Answer:

x = 53.5

Step-by-step explanation:

x is one half the difference of the intercepted arcs, that is

x = 0.5(137 - 30) = 0.5 × 107 = 53.5

8 0

3 years ago

Consider the figure. Find AB if BC = 3, BD = 5, and AD = 5. AB= ?

blondinia [14]

Answer is 9.5 First find DC by doing the Pythagorean theorem
BC is 3 BD is 5
So 3^2+ DC= 5^2
9+____=25
So DC is 4 cuz 4times 4=16

Now add AD+DC=AC

5+4=9

So BC is 3 the bottom AC is 9
3^2+9^2= 9+81=90 the sq rt of 90 is 9.5

7 0

3 years ago

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The school store sells packs of 12 pens for $2.40. Which is NOT a unit rate to describe this sale?

padilas [110]

The answer is D.

120 divided by 24 would not give you the price of ONE pen

7 0

2 years ago

Read 2 more answers

Can someone please help me please

qwelly [4]

Answer:

$1) \dfrac{12+\sqrt{-16}}{4}=\dfrac{12+\sqrt{16i^{2}}}{4}\\\\\\=\dfrac{12+4i}{4}=\dfrac{12}{4}+\dfrac{4i}{4}\\\\\\= 3 + i$

Real part = 3 & imaginary part = 1

2) 4 + 7i - 8 = 4 -8 + 7i

= -4 + 7i

Real part = -4 & imaginary part = 7

$3)\dfrac{\sqrt{9}+\sqrt{-4}}{5}=\dfrac{3+\sqrt{4i^{2}}}{5}\\\\\\=\dfrac{3}{5}+\dfrac{2i}{5}\\\\\\Real \ part = \dfrac{3}{5} \ & \ imaginary \ part = \dfrac{2}{5}$