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Murljashka [212]
2 years ago
13

Find the product: (30 gallons 3 quarts 1 pint) × 5

Mathematics
1 answer:
maks197457 [2]2 years ago
4 0

Answer:

Please mark me brainliest!!!!!!!

Step-by-step explanation:

Step 1:

Multiply each by 5, then make any necessary conversions to the other units of measurement (ie. gallon, quart, etc)

30 gallons x 5= 150 gallons

3 quarts x 5= 15 quarts

1 pint x 5= 5 pints

Step 2:

CONVERSION

1 gallon=4 quarts

1 gallon= 8 pints

1 quart= 2 pints

GALLONS: 150 gallons

QUARTS:

=15 quarts ÷ # quarts in gallon

=15/4= 3 gallons 3 quarts

PINTS:

=5 pints ÷ # pints in quart

=5/2= 2 quarts 1 pints

TOTALS:

150 gallons

3 gallons 3 quarts

2 quarts 1 pint

Since we have 5 additional quarts, and we know that 4 quarts=1 gallon, we need to convert again.

=3 quarts + 2 quarts

=5 quarts ÷ # quarts in gallon

=5/4 = 1 gallon 1 quart

FINAL TOTALS

GALLONS: 150 + 3 + 1= 154 gallons

QUARTS: 1 quart

PINTS: 1 pints

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Materials
astraxan [27]

Answer:

6.72 feet

Step-by-step explanation:

4.2 x 1.6 = 6.72

4 0
3 years ago
A boat is pulled into a dock by a rope attached to the bow of the boat and passing through a pulley on the dock that is 1 m high
Agata [3.3K]

Answer:

dy/dt = 1.02 m/s

Step-by-step explanation:

First of all, let the distance of the dock above the bow of the boat be represented by x.

Also, let the distance of the boat from the dock be represented by y.

Let z represent the length of the rope.

Now, we can use pythagoras theorem to find a relationship between x, y and z since they form a right angle triangle where the vertical part is the dock, the base represents the water and the hypotenuse represents the rope.

Thus;

x² + y² = z²

Using implicit differentiation, we have;

2x(dx/dt) + 2y(dy/dt) = 2z(dz/dt)

We are given that the dock is 1 meter above the bow. Thus, x = 1

Also, the height is not changing and so dx/dt = 0

We are told the dock is 5 feet away from the boat. Thus, y = 5

dy/dt is is the speed we are looking for which is the rate at which the boat is approaching the dock.

We are not given the value of z but we can find it by using pythagoras theorem since we know the dock is 1 meter above the bow and the boat is 5 m away.

Thus;

z = √(1² + 5²)

z = √26

We are told the rope is being pulled in at the rate of 1 m/s. Thus; dz/dt = 1

Plugging all relevant values into the differentiation equation above gives;

2(1)(0) + 2(5)(dy/dt) = 2(√26)(1)

10(dy/dt) = 2√26

Divide both sides by 10 to get:

dy/dt = (√26)/5

dy/dt = 1.02 m/s

5 0
3 years ago
If
Nitella [24]

Since profit can't be negative, the production level that'll maximize profit is approximately equal to 220.

<h3>How to find the production level that'll maximize profit?</h3>

The cost function, C(x) is given by 12000 + 400x − 2.6x² + 0.004x³ while the demand function, P(x) is given by 1600 − 8x.

Next, we would differentiate the cost function, C(x) to derive the marginal cost:

C(x) = 12000 + 400x − 2.6x² + 0.004x³

C'(x) = 400 − 5.2x + 0.012x².

Also, revenue, R(x) = x × P(x)

Revenue, R(x) = x(1600 − 8x)

Revenue, R(x) = 1600x − 8x²

Next, we would differentiate the revenue function to derive the marginal revenue:

R'(x) = 1600 - 8x

At maximum profit, the marginal revenue is equal to the marginal cost:

1600 - 8x = 400 − 5.2x + 0.012x

1600 - 8x - 400 + 5.2x - 0.012x² = 0

1200 - 2.8x - 0.012x² = 0

0.012x² + 2.8x - 1200 = 0

Solving by using the quadratic equation, we have:

x = 220.40 or x = -453.73.

Since profit can't be negative, the production level that'll maximize profit is approximately equal to 220.

Read more on maximized profit here: brainly.com/question/13800671

#SPJ1

6 0
2 years ago
I DONT KNOW WHAT IS 89090x908
never [62]

Answer:

80 893 720

Step-by-step explanation:

hope dis helps!!!!

6 0
2 years ago
In the number 4389 the digit 3 is blank times the value of the 3 in the number 6532
densk [106]
100 times as bigger because it is in the 109s
8 0
3 years ago
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