Hey there,
6x + 5 (x-2)
6x + 5x - 10
11x - 10
3x - 5 - x + 9
3x - x - 5 + 9
2x + 4
3a + 5 - 8a + 1
3 (-1) + 5 - 8(-1) + 1
-3 + 5 + 8 + 1
11
Hope this helps :))
<em>~Top♥</em>
There are 10,000 total four-digit numbers (1000 through 9999).
Multiples of 2 end in 0, 2, 4, 6, and 8. There are 9*10*10*5 = 4500 four-digit multiples of 2.
Multiples of 5 end in 0 or 5. There are 9*10*10*2 = 1800 four-digit multiples of 5.
There is redundancy between the two sets of numbers, namely those that end in 0, which are both multiples of 2 and 5. There are 9*10*10*1 = 900 four-digit multiples of both 2 and 5.
Then there are 4500 + 1800 - 900 = 5400 total four-digit numbers that are either multiples of 2 or 5, which means the remaining 4600 numbers are neither multiples of 2 nor 5.
Answer:
x=3
Step-by-step explanation:
14=7(2x-4)
14/7=2x-4
2=2x-4
2x=2+4
2x=6
x=6/2
x=3
------------
14=7(2x-4)
14=14x-28
14x=14+28
14x=42
x=42/14
x=3
<span>56 is the answer because
8*7*6/3*2</span>