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gogolik [260]
2 years ago
11

It is required that the production cost must be less than R123 505. Determine the number of devices that will be produced. Show

your solution graphically. Use interval notation and indicate the restriction on the number type of you answer. Interpret your answer
Mathematics
1 answer:
S_A_V [24]2 years ago
6 0

Answer:

The production cost is an illustration of a quadratic function

The equation of the production cost is y=ax^2+bx-c

How to determine the equation

From the complete question, we have the following parameters:

  • Computing components (a)
  • Number of devices (x),
  • Labor (b)
  • Savings on reusable material (c)

Using the instructions in the complete question, the equation of the production cost would be: y=ax^2+bx-c

Hence, the production cost is y=ax^2+bx-c

When the production cost is less than 123,505

The equation becomes

ax^2+bx-c < 123,505

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a cube measuring 1 cm on each side, what is the volume, if the cube was dropped into 28ml of water. what would the new volume be
meriva

Answer:

29 ml

Step-by-step explanation:

Vcube = 1cm×1cm×1cm = 1 cm³

1 cm³ = 1 ml

If this cube is dropped into a 28ml of water the new reading will be 29 ml.

hope this helped :)

5 0
3 years ago
What is the shape of the horizontal cross section of the
GuDViN [60]

Answer: Pentagon

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
In ΔIJK, k = 57 inches, i = 37 inches and ∠J=141°. Find ∠I, to the nearest degree.
Sonbull [250]

Answer:

<I= 15degrees

Step-by-step explanation:

Using the cosine rule formulae;

j² = i²+k²-2i cos <J

j² = 37²+57² - 2(37)(57)cos <141

j² = 1369+ 3249- 4218cos <141

j² = 4618- 4218cos <141

j² = 4618-(-3,278)

j²= 7,896

j = √7,896

j = 88.86inches

Next is to get <I

i² = j²+k²-2jk cos <I

37² = 88.86²+57² - 2(88.86)(57)cos <I

1369 = 7,896.0996+ 3249- 10,130.04cos <I

1369 = 11,145.0996 - 10,130.04cos <I

1369 - 11,145.0996 = - 10,130.04cos <I

-9,776.0996=- 10,130.04cos <I

cos <I =9,776.0996 /10,130.04

cos<I = 0.96506

<I = 15.19

<I= 15degrees

8 0
2 years ago
Which decimals written in expanded form are greater than 5.3? Check all that apply. 5 + 0.3 + 0.00 5 + 0.3 + 0.001 (5 × 1) + (2
Ksenya-84 [330]

Answer:

Any number in form of x.y = x (1) + 1/10 (y)

where x = 5 & y > 3 , or x > 5

Step-by-step explanation:

Expanded form of 5.3 = 5 (1) + 3 (1/10)

Some decimals written in expanded form that are greater than 5.3    :

5 (1) + 4 (1/10) = 5.4

6 (1) + 2 (1/10) = 6.2  

3 0
2 years ago
2. Simplify the fraction to its simplest form. 54 75​
sdas [7]

Answer:

18/25

Step-by-step explanation:

=54÷375÷3=18/25

=18/25

8 0
3 years ago
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