Answer:
19.5°
Explanation:
The energy of the mass must be conserved. The energy is given by:
1) 
where m is the mass, v is the velocity and h is the hight of the mass.
Let the height at the lowest point of the be h=0, the energy of the mass will be:
2) 
The energy when the mass comes to a stop will be:
3) 
Setting equations 2 and 3 equal and solving for height h will give:
4) 
The angle ∅ of the string with the vertical with the mass at the highest point will be given by:
5) 
where l is the lenght of the string.
Combining equations 4 and 5 and solving for ∅:
6) 
Set deer A's position to be the origin. Let 
be the distance from deer A to deer C. We're given that deer B is 95 m away from deer C, which means the length of the vector 
is 95 (or 
). Then
its B. 60 meters
Explanation:
cause I looked up a calculator and solved it
Answer:
Explanation:
For a body on a ramp with mass m, the forces acting on the body along the vertical component are the weight and the normal reaction.
The weight of the body acts in the negative y direction while the normal reaction acts in the positive y direction
Taking the sum of forces along the y component
Sum Fy = -W+R = ma
Since acceleration is zero
-W+R = m(0)
-W+R = 0
-W = -R
W = R
Hence the Normal reaction force acting on the on the body is equal to normal force
Answer:
The core beings to fuse carbon into heavier elements.
Explanation:
As the star runs out of hydrogen and helium, the energy production in the core stops, and there isn't enough outward pressure to hold the star up. The start contracts, and this heats up the core (pressure increases, temperature increases) creating temperatures high enough to fuse carbon into heavier elements like oxygen, silicon, neon, sulfur, magnesium, and iron.
But a star can sustain itself on Carbon fusion only for so long. In about 600 years (how long exactly depends on the star ) the star runs out of carbon and what happens next depends on the mass of the star; the star either collapses into a neutron star, or begins fusion heavier elements like neon.
