All categories

3 years ago

you find out that it takes 2 sec. for the swing to complete one cycle. what is the swing`s period and frequency?

1 answer:

6 0

The time it takes "to complete one cycle" is a perfect definition for period.
So the 2 sec that you measured is the swing's period.

Frequency is just 1/period (the 'reciprocal' of the period).
For this swing, the frequency is 1/(2sec) = 0.5 per second = 0.5 Hz.

( "Hertz" means "per second")

You might be interested in

Which of the following is NOT an example of the 3rd law of motion (for every Action, there is an equal but opposite reaction?

Vlad1618 [11]

Answer:

C a basketball player pushes into another one and they both fall to the left

Explanation:

I believe his is the answer because I don't see any force and not enough reaction

6 0

2 years ago

Read 2 more answers

2. Another car weighs 2000kg, you can push it .05 m/s?, how much force are you

Vesna [10]

Answer:

$\boxed {\boxed {\sf 100 \ Newtons}}$

Explanation:

We are asked to calculate the force you are applying to a car. According to Newton's Second Law of Motion, force is the product of mass and acceleration. Therefore, we can use the following formula to calculate force.

$F= m \times a$

The mass of the car is 2000 kilograms and the acceleration is 0.5 meters per second squared.

m= 2000 kg
a= 0.05 m/s²

Substitute the values into the formula.

$F= 2000 \ kg \times 0.05 \ m/s^2$

Multiply.

$F= 100 \ kg *m/s^2$

Convert the units. 1 kilogram meter per second squared is equal to 1 Newton. Our answer of 100 kilogram meters per second square is equal to 100 Newtons.

$F= 100 \ N$

You apply 100 Newtons of force to the car.

7 0

3 years ago

For a substance to change from a solid to a liquid, what must happen to its particles?

Advocard [28]

Is d I think that zona

8 0

3 years ago

Suppose that a constant force is applied to an object with a mass of 12kg, it’s creates an acceleration of 5m/s^2. The accelerat

Klio2033 [76]

Answer:

Mass of second object will be 15 kg

Explanation:

We have given mass of first object = 12 kg

Acceleration $a=5m/sec^2$

According to second law of motion we know that force F = MA

So force $F=12\times 5=60N$

As the same force is applied to the second object of acceleration $a=4m/Sec^2$

So force = ma

$60=m\times 4$

m = 15 kg

So mass of second object will be 15 kg

5 0

3 years ago

As a pole of a 2nd-order discrete-time system moves away from the origin in the z-plane, while its phase remains constant, the d

Rudik [331]

Answer:

False

Explanation:

When the location of the poles changes in the z-plane, the natural or resonant frequency (ω₀) changes which in turn changes the damped frequency (ωd) of the system.

As the poles of a 2nd-order discrete-time system moves away from the origin then natural frequency (ω₀) increases, which in turn increases damped oscillation frequency (ωd) of the system.

ωd = ω₀√(1 - ζ)

Where ζ is called damping ratio.

For small value of ζ

ωd ≈ ω₀

4 0

3 years ago