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REY [17]
2 years ago
6

A gas occupies 140 mL at 35.0 and 97kPa. what wlll the volume be at STP?

Physics
1 answer:
Cloud [144]2 years ago
4 0
The volume at STP is 22.4 dm^3, you dont need to ccalculate
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A man-made satellite of mass 6105 kg is in orbit around the earth, making one revolution in 430 minutes. What is the magnitude o
blondinia [14]

Answer:

A gravitational force of 6841.905 newtons is exerted on the satellite by the Earth.

Explanation:

At first we assume that Earth is represented by an uniform sphere, such that the man-made satellite rotates in a circular orbit around the planet. Hence, the following condition must be satisfied:

\left(\frac{4\pi^{2}}{T^{2}} \right)\cdot r = \frac{G\cdot M}{r^{2}} (1)

Where:

T - Period of rotation of the satellite, measured in seconds.

r - Distance of the satellite with respect to the center of the planet, measured in meters.

G - Gravitational constant, measured in newton-square meters per square kilogram.

M - Mass of the Earth, measured in kilograms.

Now we clear the distance of the satellite with respect to the center of the planet:

r^{3} = \frac{G\cdot M\cdot T^{2}}{4\pi^{2}}

r = \sqrt[3]{\frac{G\cdot M\cdot T^{2}}{4\pi^{2}} } (2)

If we know that G = 6.67\times 10^{-11}\,\frac{N\cdot m^{2}}{kg^{2}}, M = 6.0\times 10^{24}\,kg and T = 25800\,s, then the distance of the satellite is:

r = \sqrt[3]{\frac{\left(6.67\times 10^{-11}\,\frac{N\cdot m^{2}}{kg^{2}} \right)\cdot (6.0\times 10^{24}\,kg)\cdot (25800\,s)^{2}}{4\pi^{2}} }

r \approx 18.897\times 10^{6}\,m

The gravitational force exerted on the satellite by the Earth is determined by the Newton's Law of Gravitation:

F = \frac{G\cdot m\cdot M}{r^{2}} (3)

Where:

m - Mass of the satellite, measured in kilograms.

F - Force exerted on the satellite by the Earth, measured in newtons.

If we know that G = 6.67\times 10^{-11}\,\frac{N\cdot m^{2}}{kg^{2}}, M = 6.0\times 10^{24}\,kg, m = 6105\,kg and r \approx 18.897\times 10^{6}\,m, then the gravitational force is:

F = \frac{\left(6.67\times 10^{-11}\,\frac{N\cdot m^{2}}{kg^{2}} \right)\cdot (6105\,kg)\cdot (6\times 10^{24}\,kg)}{(18.897\times 10^{6}\,m)^{2}}

F = 6841.905\,N

A gravitational force of 6841.905 newtons is exerted on the satellite by the Earth.

4 0
3 years ago
Two capacitors have the same size of plates and the same distance 4 mm between the plates The potentials of the two plates in ca
OverLord2011 [107]

Answer:

    E = -4000 N / C

Explanation:

The potential and electric field are related

         V = - E s

          E = - V / s

we reduce the magnitudes to the SI system

          s = 4 mm (1 m / 1000 mm) = 0.004 m

we calculate

          E = - 16 /0.004

          E = -4000 N / C

8 0
3 years ago
Two astronauts are taking a spacewalk outside the International Space
Tems11 [23]

Answer:

im not sure

Explanation:

5 0
3 years ago
How does the speed of the different molecules that make up the air depend on their masses?
koban [17]
Larger molecules will move slower and smaller molecules will move faster. Did this answer your question?

8 0
2 years ago
In this experiment you will investigate which of the following properties of Faraday's law of electromagnetic induction? (Select
11Alexandr11 [23.1K]

Answer:

Answered

Explanation:

Part A

According to Faraday's law the induced emf in coil is equal to negative of its rate of change of magnetic flux time the number of turns in the coil.

\epsilon = -N\frac{d\phi}{dt}= -N\Delta\frac{BA}{\Delta t}

When an emf generated by a change of magnetic flux, produced current of whose magnetic field opposes the change  which produces it.

By the above equation the correct options are 1,2 and 4

Part B

Large signals of  frequency of 60Hz are measured by osciloscope.

Hence the correct option is part 1.

3 0
3 years ago
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