Newton’s second law of motion says when a is applied to a it causes it to.

Physics

1 answer:

n200080 [17]3 years ago

7 0

Answer:

When force is applied to an object it causes to to accelerate.

Explanation:

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during a space shuttle launch about 830,000 kg of fuel is burned in 8 min. the fuel provides the shuttle with a constant thrust,

kirill115 [55]

The shuttles acceleration in the creases as the fuel is burned because the acceleration of the obect as produced by net force is directly proportional to the magnitude of the net force.

8 0

3 years ago

HELP ASAP!!! PLEASE!!!! A driver traveling on the highway at 100km/hr notices the speed limit changes to 50km/hr as a speed came

Talja [164]

Answer:

90m

Explanation:

Speed * time

100*0.9=90m

hope this helped xx

8 0

4 years ago

With no friction, you can use the relationship between potential and kinetic energy to predict the speed of the car at the botto

Dvinal [7]

The speed of the car at the bottom of the hill is obtained as, $v = \sqrt{2gh}$

According the principle of conservation of energy, the total potential energy of the car will be converted to maximum kinetic energy when the car is at the bottom of the hill.

$K.E = P.E\\\\\frac{1}{2} mv^2 = mgh\\\\v^2 = 2gh\\\\v= \sqrt{2gh}$

where;

v is the speed of the car at the bottom of the hill
h is the height of the hill
g is acceleration due to gravity

Thus, the speed of the car at the bottom of the hill is obtained as, $v = \sqrt{2gh}$

Learn more about conservation mechanical energy here: brainly.com/question/332163

3 0

3 years ago

Two ice skaters, paula and ricardo, push off from each other. ricardo weighs more than paula. part a which skater, if either, ha

ahrayia [7]

Apply the law of conservation of momentum for this situation. The law states that the momentum of a system is constant (in absence of external forces acting on it).

The 'system' in this case are the two skaters. There is no external force on the skaters. Suppose the skaters are initially standing still. The momentum in the system is 0. This value will need to remain constant, even after the mutual push (which is a set of forces from inside the system). So we know that

(total momentum before) = (total momentum after)

Indexing the masses and velocities by the first letter of the skaters' names:

$0 = m_P\vec v_P+m_R\vec v_R\\m_P\vec v_P = m_R(-\vec v_R)$

From the last row, you can see that the skaters will have momentum of same magnitude but opposite direction, after the push off. That answers the first question: neither will have a greater momentum (both will have one of same magnitude).

Since Ricardo is heavier, from the above equality it follows that

$m_R>m_P\implies|\vec v_R|$