B. because jk and cb are on the same spot
It is more than just a quadrilateral. In fact it is going to be hard to pick.
These facts suit a square, a rectangle, a rhombus, and a parallelogram. And the above statement is true, but maybe a little harder to prove than the converse of the statement, which is the usual one you find.
The converse is "If you have a parallelagram, the diagonals bisect each other."
You might think a trapezoid deserves some mention. The diagonals of a trapezoid do not bisect each other.
Answer:
r= 0
r= 1
b= -3
x= -3
Step-by-step explanation:
4r-8r=0
-4r=0
r=0
-15=-8r-7r
-15= -15r
r=1
3b+7-1=-3
3b= -3-7+1
3b= -9
b= -9/3
b=-3
3x+1-6x=7
-3x= 7-1
-3x= 6
x= -6/3
x= -3
Answer: (3,1)
Step-by-step explanation: You put y over x and then you simplify it like a fraction and put it back in the form of a coordinate point
