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2 years ago

Can someone help answer b plzzz

Mathematics

1 answer:

BartSMP [9]2 years ago

5 0

No she is not correct
80 x.70 is 56 as you wrote, and it says 70% wait LESS THAN 30 minutes
On the left of the graph, time, you go to 30 minutes and the patients are much less (21) than 56 patients

ANSWER: No

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3 years ago

Which graph represents the solution set of the inequality x+2>6

Andreyy89

Answer:

x + 2 < 6

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3 years ago

Read 2 more answers

In triangle ABC, AC =24, the measure of angle A = 30 degree , and the measure of angle B = 45 degree . Find the area of this tri

andriy [413]

Answer:

142.932

Step-by-step explanation:

given that in triangle ABC, AC =24

Angle A = 30 and Angle B =45

If we draw altitude from C, we get

h = 24sin 30 = 12

Since BC = h (45, 45,90 triangle)

BC=12

By sine formula for triangle

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6 0

3 years ago

Elena receives $131 per year in simple interest from three investments totaling $3000. Part is invested at 3%, part at 4% an

ioda

Answer:

Elena invested $ 1,700 at 5%, $ 700 at 4%, and $ 600 at 3%.

Step-by-step explanation:

Given that Elena receives $ 131 per year in simple interest from three investments totaling $ 3000, and part is invested at 3%, part at 4% and part at 5%, and there is $ 1000 more invested at 5% than at 4%, to find the amount invested at each rate, the following calculations must be performed:

1500 x 0.05 + 500 x 0.04 + 1000 x 0.03 = 75 + 20 + 30 = 125

1600 x 0.05 + 600 x 0.04 + 800 x 0.03 = 80 + 24 + 24 = 128

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Therefore, Elena invested $ 1,700 at 5%, $ 700 at 4%, and $ 600 at 3%

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3 years ago

You want to estimate the mean amount of time college students spend on the Internet each month. How many college students must y

KonstantinChe [14]

Answer:

752.95

Step-by-step explanation:

Data provided in the question

The standard deviation of population = 210

The Margin of error = 15

The confidence level is 75%, so the z value is 1.96

Now the required sample size is

$= 1.96^2\times \frac{210^2}{15^2}$

= 752.95

Hence, the number of college students spends on the internet each month is 752.95

Simply we considered the above values so that the n could come

8 0

3 years ago