Answer:
a) The genotype of her father = "aa".
The genotype of her mother = "Aa".
The genotype of Sally is "Aa".
b) 1/2
c) 1/2
Explanation:
a) Sally's father has alkaptonuria. So, the genotype of her father is "aa". Her mother is normal. Since her brother is affected by the disease, he should be homozygous recessive (aa). This means that the mother also has one copy of "a" allele and is heterozygous dominant (Aa). A cross between Aa (mother) and aa (father) would give 50% affected progeny with "Aa" genotype. So, the genotype of Sally is "Aa".
b) The genotype of her mother= Aa
The genotype of her father = aa
Aa x aa = 1/2 Aa (affected): 1/2 aa (normal)
So, if Sally's parents have another child, there is a 1/2 probability that this child will have alkaptonuria.
c) The genotype of Sally = Aa
Genotype of the man Sally marries= aa (since he is affected with alkaptonuria)
Aa x aa= 1/2 Aa (affected): 1/2 aa (normal)
There is a 1/2 probability that their child will have alkaptonuria.
Answer:
u can take help from pictures
It's very likely that the catcus with short spines will die out faster than the cactus with long spines.
Enzymes speed up a biological reactions by lowering the activation energy.
Hope it helped you, and have a great day!
-Charlie
Thank you so much!!!!!!!!
