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oksian1 [2.3K]
3 years ago
6

Do this question if you are interested

TexFormula1" title=" - 2x ^{2} + x + 21 " alt=" - 2x ^{2} + x + 21 " align="absmiddle" class="latex-formula">
:)​
Mathematics
1 answer:
anzhelika [568]3 years ago
4 0

-2x² + x + 21

Common factor

-2x² + x + 21

-1(2x²-x-21)

Use the sum-product pattern

-1(2x²-x-21)

-1(2x² +6x-7x - 21)

Common factor from the two pairs

-1(2x² + 6x - 7x - 21)

-1(2x(x + 3) - 7(x+3))

Rewrite in factored form

-1(2x(x + 3) - 7(x+3))

-1(2x-7)(x+3)

Answer :-{\large{ \red{{{-1(2x-7)(x+3)}}}}}

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This may or may not be right.

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3 years ago
PLZ ASWER ASAP!!!!!!!!!!!
geniusboy [140]

Answer:

f(x) = 6x² - 24x + 21

Step-by-step explanation:

The equation of a quadratic function in vertex form is

f(x) = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k ) = (2, - 3 ) , then

f(x) = a(x - 2)² - 3

To find a substitute (1, 3 ) into the equation

3 = 1(1 - 2)² - 3

3 = a(- 1)² - 3

3 = a - 3 ( add 3 to both sides )

6 = a

f(x) = 6(x - 2)² - 3 ← in vertex form

     = 6(x² - 4x + 4) - 3

     = 6x² - 24x + 24 - 3

f(x) = 6x² - 24x + 21 ← in standard form

4 0
3 years ago
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A number increased by 7
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Step-by-step explanation:

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Enjoy and it would be good if you gave more points

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