Answer:
9.35975609756
Step-by-step explanation:
Its about this I just put it into a calculator
Answer:
Is the power produced directly proportional to the wind speed.
No.
A proportional function can be described as y = a * x
So (0, 0) is on the graph, not (3, 0).
0 / 3 = 0
3800/6 = 633.33
7600/9 = 844.44
13600/12 = 1133.33
The quotient y/x should be always the same.
<span>Acceleration of a passenger is centripetal acceleration, since the Ferris wheel is assumed at uniform speed:
a = omega^2*r
omega and r in terms of given data:
omega = 2*Pi/T
r = d/2
Thus:
a = 2*Pi^2*d/T^2
What forces cause this acceleration for the passenger, at either top or bottom?
At top (acceleration is downward):
Weight (m*g): downward
Normal force (Ntop): upward
Thus Newton's 2nd law reads:
m*g - Ntop = m*a
At top (acceleration is upward):
Weight (m*g): downward
Normal force (Nbottom): upward
Thus Newton's 2nd law reads:
Nbottom - m*g = m*a
Solve for normal forces in both cases. Normal force is apparent weight, the weight that the passenger thinks is her weight when measuring by any method in the gondola reference frame:
Ntop = m*(g - a)
Nbottom = m*(g + a)
Substitute a:
Ntop = m*(g - 2*Pi^2*d/T^2)
Nbottom = m*(g + 2*Pi^2*d/T^2)
We are interested in the ratio of weight (gondola reference frame weight to weight when on the ground):
Ntop/(m*g) = m*(g - 2*Pi^2*d/T^2)/(m*g)
Nbottom/(m*g) = m*(g + 2*Pi^2*d/T^2)/(m*g)
Simplify:
Ntop/(m*g) = 1 - 2*Pi^2*d/(g*T^2)
Nbottom/(m*g) = 1 + 2*Pi^2*d/(g*T^2)
Data:
d:=22 m; T:=12.5 sec; g:=9.8 N/kg;
Results:
Ntop/(m*g) = 71.64%...she feels "light"
Nbottom/(m*g) = 128.4%...she feels "heavy"</span>
Answer:
|x + 6| = 2
Step-by-step explanation:
|x - b| = c
b is the centre: (-4-8)/2 = -6
b = -6
c is the distance from the centre
-6 - (-8) = -6 + 8 = 2
Or,
-4 - (-6) = -4 + 6 = 2
| x - (-6)| = 2
|x + 6| = 2
The answer to what is the length of AB and the correct value is 20
I got a 100% on test
