Answer:
1, 3, 7, 21
Step by step explanation:
Use a calculator. I would walk you through it, but it should be simple.
2x^2-4x-30 would be your answer
<span><span>(<span><span>2x</span>−10</span>)</span><span>(<span>x+3</span>)
</span></span><span>=<span><span>(<span><span>2x</span>+<span>−10</span></span>)</span><span>(<span>x+3</span>)
</span></span></span><span>=<span><span><span><span><span>(<span>2x</span>)</span><span>(x)</span></span>+<span><span>(<span>2x</span>)</span><span>(3)</span></span></span>+<span><span>(<span>−10</span>)</span><span>(x)</span></span></span>+<span><span>(<span>−10</span>)</span><span>(3)
</span></span></span></span><span>=<span><span><span><span>2<span>x2</span></span>+<span>6x</span></span>−<span>10x</span></span>−30
</span></span><span>=<span><span><span>2<span>x2</span></span>−<span>4x</span></span>−<span>30</span></span></span>
Answer:
So we have 
.
Step-by-step explanation:
Ok so we are in quadrant 2, that means sine is positive while cosine is negative.
We are given 
.
So to find the opposite we will just use the Pythagorean Theorem.
This is the opposite side.
Now to find 
and 
.
.
Some teachers do not like the radical on bottom so we will rationalize the denominator by multiplying the numerator and denominator by sqrt(5).
So 
.
And now 
.
So we have .
I’m assuming the question is z7 = 8 ; in that case z= 8/7
