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2 years ago

Divide x^3/x brainliest to best correct answer

Mathematics

2 answers:

lana66690 [7]2 years ago

7 0

Answer:

x^2

...............................................

Lostsunrise [7]2 years ago

5 0

Answer:

x^2

Step-by-step explanation:

x3/x1

=x*x*x/x

=x*x

=x2

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Carbon has a half life of 5730 years. How much carbon would be left after 3 half life's with 56 grams

Maslowich

Answer:

how much was originally?

Step-by-step explanation:

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3 years ago

It is estimated that 75% of all young adults between the ages of 18-35 do not have a landline in their homes and only use a cell

Mademuasel [1]

Answer:

a) 75

b) 4.33

c) 0.75

d) $3.2 \times 10^{-13}$ probability that no one in a simple random sample of 100 young adults owns a landline

e) $6.2 \times 10^{-61}$ probability that everyone in a simple random sample of 100 young adults owns a landline.

f) Binomial, with $n = 100, p = 0.75$

g) $4.5 \times 10^{-8}$ probability that exactly half the young adults in a simple random sample of 100 do not own a landline.

Step-by-step explanation:

For each young adult, there are only two possible outcomes. Either they do not own a landline, or they do. The probability of an young adult not having a landline is independent of any other adult, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

75% of all young adults between the ages of 18-35 do not have a landline in their homes and only use a cell phone at home.

This means that $p = 0.75$

(a) On average, how many young adults do not own a landline in a random sample of 100?

Sample of 100, so $n = 100$

$E(X) = np = 100(0.75) = 75$

(b) What is the standard deviation of probability of young adults who do not own a landline in a simple random sample of 100?

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100(0.75)(0.25)} = 4.33$

(c) What is the proportion of young adults who do not own a landline?

The estimation, of 75% = 0.75.

(d) What is the probability that no one in a simple random sample of 100 young adults owns a landline?

This is P(X = 100), that is, all do not own. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 100) = C_{100,100}.(0.75)^{100}.(0.25)^{0} = 3.2 \times 10^{-13}$

$3.2 \times 10^{-13}$ probability that no one in a simple random sample of 100 young adults owns a landline.

(e) What is the probability that everyone in a simple random sample of 100 young adults owns a landline?

This is P(X = 0), that is, all own. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{100,0}.(0.75)^{0}.(0.25)^{100} = 6.2 \times 10^{-61}$

$6.2 \times 10^{-61}$ probability that everyone in a simple random sample of 100 young adults owns a landline.

(f) What is the distribution of the number of young adults in a sample of 100 who do not own a landline?

Binomial, with $n = 100, p = 0.75$

(g) What is the probability that exactly half the young adults in a simple random sample of 100 do not own a landline?

This is P(X = 50). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 50) = C_{100,50}.(0.75)^{50}.(0.25)^{50} = 4.5 \times 10^{-8}$

$4.5 \times 10^{-8}$ probability that exactly half the young adults in a simple random sample of 100 do not own a landline.

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2 years ago

Math test pls help me

Natalija [7]

Answer:

D. $\frac{45}{x^{10}}$

Step-by-step explanation:

$(3 {x}^{ - 4} )^{2} (5 {x}^{ - 2} ) \\ \\ = (9 {x}^{ - 8} )(5 {x}^{ - 2} ) \\ \\ = 9 \times 5 \times {x}^{ - 8 - 2} \\ \\ = 45 {x}^{ - 10} \\ \\ = \frac{45}{ {x}^{10} }$

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2 years ago

Given a standard 52-card deck and a 5-card hand, how many unique hands are there with at least 1 club or no aces?

Ludmilka [50]

Edit: Wrong solution

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2 years ago

How can I solve prove that questions in trigonometry.

madam [21]

Step-by-step explanation:

Tip 1) Always Start from the More Complex Side.

Tip 2) Express everything into Sine and Cosine.

Tip 3) Combine Terms into a Single Fraction.

Tip 4) Use Pythagorean Identities to transform between sin²x and cos²x.

Tip 5) Know when to Apply Double Angle Formula (DAF)

I am also from nepal...very happy to see you..

7 0

1 year ago