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Yuliya22 [10]
2 years ago
5

Divide x^3/x brainliest to best correct answer

Mathematics
2 answers:
lana66690 [7]2 years ago
7 0

Answer:

x^2

...............................................

Lostsunrise [7]2 years ago
5 0

Answer:

x^2

Step-by-step explanation:

x3/x1

=x*x*x/x

=x*x

=x2

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80Divided by 3 plz help
mojhsa [17]

Answer:

Your answer is 26.667

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3 years ago
A map of an island is shown on a half-centimetre grid,
SOVA2 [1]

Answer:

The answer is b.

Step-by-step explanation:

4 0
3 years ago
We expect a car's highway gas mileage to be related to its city gas mileage (in miles per gallon, mpg). Data for all 1137 vehicl
USPshnik [31]

Answer:

a) As we can see on the equation given the slope os 1.033 since is the value next to the city mpg (independent variable)

And on this case since the value for the slope is positive the best interpretation is:

E. On the average, highway mileage increases by 1.033 mpg for each additional mpg in city mileage

Because we see the if we increase on 1 unit the city mpg then the highway mpg would increase 1.033

b) For this case as we can see in the model the free term correspond to 6.785 and that correspond to the intercept for this case.

And the best interpretation is given by:

B. Because this is the highway mileage for zero city mpg.

For this reason is not meaningful since we are not interested on 0 or negative city mpg.

c) highway mpg = 6.785 + (1.033 × 18)=25.38 mpg

highway mpg = 6.785 + (1.033 × 25)=32.61 mpg

d) See the figure attached.

Step-by-step explanation:

For this case we have the following linear model:

highway mpg = 6.785 + (1.033 × city mpg)

(a) What is the slope of this line? Say in words what the numerical value of the slope tells us.

As we can see on the equation given the slope os 1.033 since is the value next to the city mpg (independent variable)

And on this case since the value for the slope is positive the best interpretation is:

E. On the average, highway mileage increases by 1.033 mpg for each additional mpg in city mileage

Because we see the if we increase on 1 unit the city mpg then the highway mpg would increase 1.033

(b) What is the intercept? (Enter your answer to three decimal places.)mpgExplain why the value of the intercept is not statistically meaningful.

For this case as we can see in the model the free term correspond to 6.785 and that correspond to the intercept for this case.

And the best interpretation is given by:

B. Because this is the highway mileage for zero city mpg.

For this reason is not meaningful since we are not interested on 0 or negative city mpg.

(c) Find the predicted highway mileage for a car that gets 18 miles per gallon in the city. (Round your answer to two decimal places.)______ mpgFind the predicted highway mileage for a car that gets 25 miles per gallon in the city. (Round your answer to two decimal places.)______ mpg

For this case we just need to replace into the formula and we got:

highway mpg = 6.785 + (1.033 × 18)=25.38 mpg

highway mpg = 6.785 + (1.033 × 25)=32.61 mpg

(d) Draw a graph of the regression line for city mileages between 10 and 50 mpg. (Be sure to show the scales for the x and y axes.)

See the figure attached

6 0
3 years ago
What is the perimeter?and how to I find it
Lelechka [254]

Answer:

is there more info? I don't think this can be solved with given numbers could you take a more zoomed out photo?

5 0
3 years ago
Read 2 more answers
Please help w this! Its a calculus question! look at the picture for the problem,
neonofarm [45]

Since you mentioned calculus, perhaps you're supposed to find the area by integration.

The square is circumscribed by a circle of radius 6, so its diagonal (equal to the diameter) has length 12. The lengths of a square's side and its diagonal occur in a ratio of 1 to sqrt(2), so the square has side length 6sqrt(2). This means its sides occur on the lines x=\pm3\sqrt2 and y=\pm3\sqrt2.

Let R be the region bounded by the line x=3\sqrt2 and the circle x^2+y^2=36 (the rightmost blue region). The right side of the circle can be expressed in terms of x as a function of y:

x^2+y^2=36\implies x=\sqrt{36-y^2}

Then the area of this circular segment is

\displaystyle\iint_R\mathrm dA=\int_{-3\sqrt2}^{3\sqrt2}\int_{3\sqrt2}^{\sqrt{36-y^2}}\,\mathrm dx\,\mathrm dy

=\displaystyle\int_{-3\sqrt2}^{3\sqrt2}(\sqrt{36-y^2}-3\sqrt2)\,\mathrm dy

Substitute y=6\sin t, so that \mathrm dy=6\cos t\,\mathrm dt

=\displaystyle\int_{-\pi/4}^{\pi/4}6\cos t(\sqrt{36-(6\sin t)^2}-3\sqrt2)\,\mathrm dt

=\displaystyle\int_{-\pi/4}^{\pi/4}(36\cos^2t-18\sqrt2\cos t)\,\mathrm dt=9\pi-18

Then the area of the entire blue region is 4 times this, a total of \boxed{36\pi-72}.

Alternatively, you can compute the area of R in polar coordinates. The line x=3\sqrt2 becomes r=3\sqrt2\sec\theta, while the circle is given by r=6. The two curves intersect at \theta=\pm\dfrac\pi4, so that

\displaystyle\iint_R\mathrm dA=\int_{-\pi/4}^{\pi/4}\int_{3\sqrt2\sec\theta}^6r\,\mathrm dr\,\mathrm d\theta

=\displaystyle\frac12\int_{-\pi/4}^{\pi/4}(36-18\sec^2\theta)\,\mathrm d\theta=9\pi-18

so again the total area would be 36\pi-72.

Or you can omit using calculus altogether and rely on some basic geometric facts. The region R is a circular segment subtended by a central angle of \dfrac\pi2 radians. Then its area is

\dfrac{6^2\left(\frac\pi2-\sin\frac\pi2\right)}2=9\pi-18

so the total area is, once again, 36\pi-72.

An even simpler way is to subtract the area of the square from the area of the circle.

\pi6^2-(6\sqrt2)^2=36\pi-72

6 0
3 years ago
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