1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tiny-mole [99]
3 years ago
7

Monte's Autorana is having an end-of-year clearance in which the TV ads proclaim that

Mathematics
1 answer:
11111nata11111 [884]3 years ago
7 0

Answer:

No

Step-by-step explanation:

We first write out $17,500 as a multiplication to 5%

New price = 17500 x 1.05 = 18375  = $18,375

18375-17500 = 875

We then work out the tax on just the mark up of $875 increase

20% mark up = 875 x 0.20 = 175

18.375+175 = 18550

= $18,550 charge to be considered for 5%

However Monte would argue that tax on tax also applies to 875 x 1.20 = 1050

=$1050 and he is just asking to meet half tax costs an extra 10% of his own tax back of 17.500 x 20% that he paid = 17500 x 0.20 = 3500

tax he paid inclusive or non inclusive would be the same.

= $3500

10% of this = 3500 x 0.10 = 350  

18550+350 = 18,900

Therefore it is not dishonest if mentioned in the terms and conditions.

We also universally can round 5% up by applying other charges to include promotion costs and even apply more for administration costs.

You might be interested in
HELP!!! The graph is at the top! Will mark as brainliest answer!!
Alex777 [14]

Answer:

The value of BEF = 36°

Step-by-step explanation:

Given:

Angle AED = 90°

Angle BEF = 3x°

Angle CEF = 54°

Find;

The value of BEF

Computation:

We know that;

Angle AED = Angle BEC (Vertical opposite angle)

So,

Angle AED = Angle Angle BEF + Angle CEF

90 = 3x + 54

3x = 90 - 54

3x = 36

x = 36 / 3

x = 12

The value of BEF = 3x

The value of BEF = 3(12)

The value of BEF = 36°

4 0
2 years ago
PLEASE HELP An algebraic ___ is a mathematical phrase
scoundrel [369]
Answer: Expression

Hope this helps :)
5 0
2 years ago
Read 2 more answers
Is this a linear function ?<br><img src="https://tex.z-dn.net/?f=y%20%3D%20%20-%203%20%5E%7B2%7D%20%20%2B%202" id="TexFormula1"
Slav-nsk [51]
No its not a linear function i think
8 0
3 years ago
3 x 104 + 2.5 x 105 =<br> A. 0.5 x 105<br> B. 2.8 x 105<br> C. 3.25 x 105<br> D. 5.5 x 109
WITCHER [35]

Answer:

574.5 A) 52.5 B) 294 C) 341.25 D) 599.5

Step-by-step explanation:

3*104+2.5*105=312+262.5=574.5

A) 0.5*105=52.5

B) 2.8*105=294

C) 3.25*105=341.25

D) 5.5*109=599.5

6 0
3 years ago
Based on the number of voids, a ferrite slab is classified as either high, medium, or low. Historically, 5% of the slabs are cla
AnnyKZ [126]

Answer:

(a) Name: Multinomial distribution

Parameters: p_1 = 5\%   p_2 = 85\%   p_3 = 10\%  n = 20

(b) Range: \{(x,y,z)| x + y + z=20\}

(c) Name: Binomial distribution

Parameters: p_1 = 5\%      n = 20

(d)\ E(x) = 1   Var(x) = 0.95

(e)\ P(X = 1, Y = 17, Z = 3) = 0

(f)\ P(X \le 1, Y = 17, Z = 3) =0.07195

(g)\ P(X \le 1) = 0.7359

(h)\ E(Y) = 17

Step-by-step explanation:

Given

p_1 = 5\%

p_2 = 85\%

p_3 = 10\%

n = 20

X \to High Slabs

Y \to Medium Slabs

Z \to Low Slabs

Solving (a): Names and values of joint pdf of X, Y and Z

Given that:

X \to Number of voids considered as high slabs

Y \to Number of voids considered as medium slabs

Z \to Number of voids considered as low slabs

Since the variables are more than 2 (2 means binomial), then the name is multinomial distribution

The parameters are:

p_1 = 5\%   p_2 = 85\%   p_3 = 10\%  n = 20

And the mass function is:

f_{XYZ} = P(X = x; Y = y; Z = z) = \frac{n!}{x!y!z!} * p_1^xp_2^yp_3^z

Solving (b): The range of the joint pdf of X, Y and Z

Given that:

n = 20

The number of voids (x, y and z) cannot be negative and they must be integers; So:

x + y + z = n

x + y + z = 20

Hence, the range is:

\{(x,y,z)| x + y + z=20\}

Solving (c): Names and values of marginal pdf of X

We have the following parameters attributed to X:

p_1 = 5\% and n = 20

Hence, the name is: Binomial distribution

Solving (d): E(x) and Var(x)

In (c), we have:

p_1 = 5\% and n = 20

E(x) = p_1* n

E(x) = 5\% * 20

E(x) = 1

Var(x) = E(x) * (1 - p_1)

Var(x) = 1 * (1 - 5\%)

Var(x) = 1 * 0.95

Var(x) = 0.95

(e)\ P(X = 1, Y = 17, Z = 3)

In (b), we have: x + y + z = 20

However, the given values of x in this question implies that:

x + y + z = 1 + 17 + 3

x + y + z = 21

Hence:

P(X = 1, Y = 17, Z = 3) = 0

(f)\ P{X \le 1, Y = 17, Z = 3)

This question implies that:

P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3) + P(X = 1, Y = 17, Z = 3)

Because

0, 1 \le 1 --- for x

In (e), we have:

P(X = 1, Y = 17, Z = 3) = 0

So:

P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3) +0

P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3)

In (a), we have:

f_{XYZ} = P(X = x; Y = y; Z = z) = \frac{n!}{x!y!z!} * p_1^xp_2^yp_3^z

So:

P(X=0; Y=17; Z = 3) = \frac{20!}{0! * 17! * 3!} * (5\%)^0 * (85\%)^{17} * (10\%)^{3}

P(X=0; Y=17; Z = 3) = \frac{20!}{1 * 17! * 3!} * 1 * (85\%)^{17} * (10\%)^{3}

P(X=0; Y=17; Z = 3) = \frac{20!}{17! * 3!} * (85\%)^{17} * (10\%)^{3}

Expand

P(X=0; Y=17; Z = 3) = \frac{20*19*18*17!}{17! * 3*2*1} * (85\%)^{17} * (10\%)^{3}

P(X=0; Y=17; Z = 3) = \frac{20*19*18}{6} * (85\%)^{17} * (10\%)^{3}

P(X=0; Y=17; Z = 3) = 20*19*3 * (85\%)^{17} * (10\%)^{3}

Using a calculator, we have:

P(X=0; Y=17; Z = 3) = 0.07195

So:

P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3)

P(X \le 1, Y = 17, Z = 3) =0.07195

(g)\ P(X \le 1)

This implies that:

P(X \le 1) = P(X = 0) + P(X = 1)

In (c), we established that X is a binomial distribution with the following parameters:

p_1 = 5\%      n = 20

Such that:

P(X=x) = ^nC_x * p_1^x * (1 - p_1)^{n - x}

So:

P(X=0) = ^{20}C_0 * (5\%)^0 * (1 - 5\%)^{20 - 0}

P(X=0) = ^{20}C_0 * 1 * (1 - 5\%)^{20}

P(X=0) = 1 * 1 * (95\%)^{20}

P(X=0) = 0.3585

P(X=1) = ^{20}C_1 * (5\%)^1 * (1 - 5\%)^{20 - 1}

P(X=1) = 20 * (5\%)* (1 - 5\%)^{19}

P(X=1) = 0.3774

So:

P(X \le 1) = P(X = 0) + P(X = 1)

P(X \le 1) = 0.3585 + 0.3774

P(X \le 1) = 0.7359

(h)\ E(Y)

Y has the following parameters

p_2 = 85\%  and    n = 20

E(Y) = p_2 * n

E(Y) = 85\% * 20

E(Y) = 17

8 0
3 years ago
Other questions:
  • HELPPPP me this shyt annoying me lol
    10·1 answer
  • Solve for x please!
    12·1 answer
  • If f(x)=15x+3, then f-1(x)=
    12·1 answer
  • 2,408,615 in expanded
    8·1 answer
  • The probability that a student has a Visa card (event V) is .63. The probability that a student has a MasterCard (event M) is .1
    11·1 answer
  • Which is equivalent to 3 cube root 125
    15·2 answers
  • Ariana wants to ride her bicycle 37 miles this week. She has already ridden 14 miles. If she rides for 5 more days, write and so
    13·1 answer
  • In the given figure p=120° and y : z=2 : 3 Find x, y and z​
    9·1 answer
  • PLEASE ANSWER ANY PROBLEM ASAP THANK YOU SO MUCH
    14·2 answers
  • a ladder on a fire truck has its base 6 ft above the ground. the maximum length of the ladder is 100 ft. if the ladder's greates
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!