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serg [7]
2 years ago
13

Help!!!Solve for h:6.1h = 2.44​

Mathematics
1 answer:
Anna007 [38]2 years ago
5 0

Answer:

h=0.4

Step-by-step explanation:

6.1h=2.44

h=2.44/6.1

h=0.4

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Can someone please give me the answers
Angelina_Jolie [31]

Answer:

1) 3

2)9

3)18

4)18k

5)18 and k

6)k/3

7)k

8)3

9)9 + k/3

10) 18k - 9

3 0
3 years ago
Evaluate the surface integral:S
rjkz [21]
Assuming S does not include the plane z=0, we can parameterize the region in spherical coordinates using

\mathbf r(u,v)=\left\langle3\cos u\sin v,3\sin u\sin v,3\cos v\right\rangle

where 0\le u\le2\pi and 0\le v\le\dfrac\pi/2. We then have

x^2+y^2=9\cos^2u\sin^2v+9\sin^2u\sin^2v=9\sin^2v
(x^2+y^2)=9\sin^2v(3\cos v)=27\sin^2v\cos v

Then the surface integral is equivalent to

\displaystyle\iint_S(x^2+y^2)z\,\mathrm dS=27\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^2v\cos v\left\|\frac{\partial\mathbf r(u,v)}{\partial u}\times \frac{\partial\mathbf r(u,v)}{\partial u}\right\|\,\mathrm dv\,\mathrm du

We have

\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle
\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle3\cos u\cos v,3\sin u\cos v,-3\sin v\rangle
\implies\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle-9\cos u\sin^2v,-9\sin u\sin^2v,-9\cos v\sin v\rangle
\implies\left\|\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}\|=9\sin v

So the surface integral is equivalent to

\displaystyle243\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv\,\mathrm du
=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv
=\displaystyle486\pi\int_{w=0}^{w=1}w^3\,\mathrm dw

where w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv.

=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}
=\dfrac{243}2\pi
4 0
3 years ago
By what percent will a fraction decrease if its numerator is decreased by 50% and its denominator is decreased by 25%?
il63 [147K]
The answer is 66.6666%
3 0
3 years ago
Read 2 more answers
How to solve this problem
Arisa [49]
First, you solve the square root:

9+ \sqrt{-4}

Knowing that the square root of a negative number doesn't exist:

9+ \sqrt{-4}
9+2i is your answer.


Hope it helped,

Happy homework/ study/ exam!


4 0
3 years ago
PLEASE HELP TIMED
kogti [31]
Jjbivhvu this need a bit more
5 0
2 years ago
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