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Svetradugi [14.3K]
2 years ago
12

Find the original price before discount if discount is 25% and original price $25​

Mathematics
1 answer:
Lera25 [3.4K]2 years ago
4 0

Answer:

umm im kinda confused but this may be the answer if you clarified.

25 is the answer after the discount but before the discount it would be  31.25 beccause...

Step-by-step explanation:

25 percent of 25= 6.25 so

6.25 plus 25= 31.25

hope this helped!

brainliest

-S

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Answer:

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in 2010 the population of rhode island was approximately 1053000. if the population decrease was 0.3% find the population of rho
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3 years ago
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
marusya05 [52]

Answer:

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

\hat p =\frac{955-812}{955}= 0.150

0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131

0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169

And the 90% confidence interval would be given (0.131;0.169).

Step-by-step explanation:

We have the following info given:

n= 955 represent the sampel size slected

x = 812 number of students who read above the eighth grade level

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

\hat p =\frac{955-812}{955}= 0.150

The confidence interval for the proportion  would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 90% confidence interval the significance is \alpha=1-0.9=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the normal standard distribution and we got.

z_{\alpha/2}=1.64

And replacing into the confidence interval formula we got:

0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131

0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169

And the 90% confidence interval would be given (0.131;0.169).

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3 years ago
Help with both questions offering 10 points
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Answer:

\:\mathrm{First\: problem:\:}-2,\\\:\mathrm{Second\: problem:\: }-3

Step-by-step explanation:

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m=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1}

Plugging in any two points in the table we have:

<u>First problem:</u>

<u />m=\frac{1-5}{2-0}=\frac{-4}{2}=\fbox{$-2$}<u />

<u>Second problem:</u>

<u />m=\frac{-1-5}{2-0}=\frac{-6}{2}=\fbox{$-3$}<u />

8 0
3 years ago
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Answer:

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Step-by-step explanation:

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Hope this helps

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2 years ago
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