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AveGali [126]
3 years ago
8

25 points if you answer please answer

Mathematics
2 answers:
Airida [17]3 years ago
6 0

Answer:

The answer is D

Step-by-step explanation:

because the left sides answer is -16 and so on the right side you must make it -16 as well by subtracting -31.

mezya [45]3 years ago
5 0
The answer to your question is D
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Sharon has 23 toy car that are colored red, blue, and white. She has 4 red cars, 2 fewer blue cars than red and 5 more purple ho
podryga [215]

Answer:

13 white cars

Step-by-step explanation:

Let us represent:

Number of

Red cars = x

Blue cars = y

White cars = z

Sharon has 23 toy car that are colored red, blue, and white.

x + y + z = 23

x = 4

2 fewer blue cars than red

y - 2 = x

y - 2 = 4

y = 4 + 2

y = 6

Hence,

x + y + z = 23

4 +

Number of white cars is calculated as:

23 - (6 + 4)

23 - 10

= 13 white cars

8 0
3 years ago
Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt
polet [3.4K]

If you're just integrating a vector-valued function, you just integrate each component:

\displaystyle\int(\sec^2t\,\hat\imath+t(t^2-1)^8\,\hat\jmath+t^7\ln t\,\hat k)\,\mathrm dt

=\displaystyle\left(\int\sec^2t\,\mathrm dt\right)\hat\imath+\left(\int t(t^2-1)^8\,\mathrm dt\right)\hat\jmath+\left(\int t^7\ln t\,\mathrm dt\right)\hat k

The first integral is trivial since (\tan t)'=\sec^2t.

The second can be done by substituting u=t^2-1:

u=t^2-1\implies\mathrm du=2t\,\mathrm dt\implies\displaystyle\frac12\int u^8\,\mathrm du=\frac1{18}(t^2-1)^9+C

The third can be found by integrating by parts:

u=\ln t\implies\mathrm du=\dfrac{\mathrm dt}t

\mathrm dv=t^7\,\mathrm dt\implies v=\dfrac18t^8

\displaystyle\int t^7\ln t\,\mathrm dt=\frac18t^8\ln t-\frac18\int t^7\,\mathrm dt=\frac18t^8\ln t-\frac1{64}t^8+C

8 0
3 years ago
3. Is the relation {(1,2), (3, 10), (2,8), (5,<br> 10)} a function?<br> a) yes<br> b) no<br> a
Sedaia [141]

Answer:

the answer is yes

Step-by-step explanation:

4 0
3 years ago
In ΔOPQ, o = 5.9 cm, q = 5.5 cm and ∠Q=142°. Find all possible values of ∠O, to the nearest 10th of a degree.
Katyanochek1 [597]

Answer: no possible triangles

Step-by-step explanation: just submit nothing or like [ ]

4 0
2 years ago
For this Prism to be a right prism, all the lateral faces must be rectangles. Is enough infromation given to prove the lateral f
Ilia_Sergeevich [38]

Answer:

yes i think that is definitely enough intonation

6 0
3 years ago
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