I don't know what you are exactly asking me to do!?!?
Answer:
Cable attached height (Perpendicular) = 10√3 m
Step-by-step explanation:
Given:
Length of cable (Hypotenuse) = 20 m
Angle θ = 60°
Find:
Cable attached height (Perpendicular)
Computation:
Perpendicular/Hypotenuse = Sinθ
Perpendicular/20 = Sin 60
Perpendicular/20 = √3 / 2
Perpendicular = 10√3
Cable attached height (Perpendicular) = 10√3 m
I thank the answer is B y=x-35
As the 2 quadrilaterals are congruent the sides of one quadrilateral are equal to the corresponding sides of the other quadrilateral
Hence,
AB = PQ
RQ = BC
AD = PS
DC = RS
Since terms for both AB and PQ are given we can equate the terms and find m
5m -9 = m + 11
5m -m = 11 + 9
4m = 20
m = 5
Correct answer is D , 5