Answer:
7.4.
Explanation:
∵ pH = -log[H₃O⁺].
∴ pH = -log(2.5 x 10⁻⁷) = 6.6.
<em>∵ pH + pOH = 14.</em>
<em />
∴ pOH = 14.0 - pH = 14.0 - 6.6 = 7.4.
Answer:
1Na₂S + 1Cd(C₂H₃O₂)₂ → 1CdS + 2NaC₂H₃O
Explanation:
1Na₂S + 1Cd(C₂H₃O₂)₂ → 1CdS + 1NaC₂H₃O₂
1Na₂S + 1Cd(C₂H₃O₂)₂ → 1CdS + 2NaC₂H₃O₂
(on the reactant side there are two molecules of C₂H₃O₂ and 2 atoms of Na, so in order to balance that we put the coefficient 2 on NAC₂H₃O₂)
So the final product is
1Na₂S + 1Cd(C₂H₃O₂)₂ → 1CdS + 2NaC₂H₃O₂
In chemistry, a single bond is a chemical bond between two atoms involving two valence electrons. That is, the atoms share one pair of electrons where the bond forms. Therefore, a single bond is a type of covalent bond.
Answer:
ola what do u need to do?
Answer:
V = 56.72 L
Explanation:
Given data:
Number of mole of neon gas = 0.83 mol
Temperature = 35°C
Pressure = 0.37 atm
Volume of gas = ?
Solution;
Temperature = 35°C (35+273 =308K)
Formula:
PV = nRT
R = general gas constant = 0.0821 atm.L/mol.K
Now we will put the values in formula.
V = nRT/P
V = 0.83 mol ×0.0821 atm.L/mol.K ×308K / 0.37 atm
V = 20.99 L/ 0.37
V = 56.72 L
