Rubidium would exhibit the greatest shielding [ effect. ]
..............................
Answer:
Explanation:
m / z = 20 , 21 , 22
m / 1 = 20 , 21 , 22
m = 20 , 21 , 22 .
ratio of isotopes = 112 : 0.21 : 11.1
Average atomic mass = (112 x 20 + .21 x 21 + 11.1 x 22) / (112 + .21 + 11.1 )
= (2240 + 4.41 + 244.2) / 123.31
= 2488.61 / 123.31
= 20.18
Ans: Moles of Fe(OH)2 produced is 5.35 moles.
Given reaction:
Fe(s) + 2NiO(OH) (s) + 2H2O(l) → Fe(OH)2(s) + 2Ni(OH)2(aq)
Based on the reaction stoichiometry:
1 mole of Fe reacts with 2 moles of NiO(OH) to produce 1 mole of Fe(OH)2
It is given that there are:
5.35 moles of Fe
7.65 moles of NiO(OH)
Here the limiting reagent is Fe
Therefore, number of moles of Fe(OH)2 produced is 5.35 moles.
Answer:
0.0613 L
Explanation:
Given data
- Initial pressure (P₁): 1.00 atm
- Initial volume (V₁): 1.84 L
- Final pressure (P₂): 30.0 atm
Since we are dealing with an ideal gas, we can calculate the final volume using Boyle's law.
P₁ × V₁ = P₂ × V₂
V₂ = P₁ × V₁ / P₂
V₂ = 1.00 atm × 1.84 L / 30.0 atm
V₂ = 0.0613 L