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2 years ago

Determine whether or not the mixing of each of the two solutions indicated below will result in a buffer.

Chemistry

1 answer:

Makovka662 [10]2 years ago

4 0

Sinve CH3NH2 is weak base and its salt is CH3NH3Cl, mixing 125.0 mL of CH3NH2 and 120.0 mL of CH3NH3Cl so produce a buffer.

<h3>What is a buffer?</h3>

A buffer is a solution which resists changes to its pH when a small quantity of strong acid or base is added to it..

A buffer is made from a weak acid and its salt or a weak base and its salt.

From the given options, CH3NH2 is weak base and its salt is CH3NH3Cl.

Therefore, mixing 125.0 mL of CH3NH2 and 120.0 mL of CH3NH3Cl so produce a buffer.

Learn more about buffers at: brainly.com/question/1385846

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Answer:

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Option 3 shows a balanced equation.

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3 years ago

A compound is 75.46% Carbon, 4.43% hydrogen and 20.10% Oxygen by mass. it has a molecular weight of 318.31g/mol. what is the mol

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Answer:

No.of moles of C is , n = mass/molar mass = 75.46 g / 12 (g/mol) = 6.3 moles No.of moles of H is , n' = mass/molar mass = 4.43 g / 1.0(g/mol) = 4.43 moles No.of moles of O is , n'' = mass/molar mass = 20.10 g / 16(g/mol) =1.25 moles Ratio to the no.of moles of C,H& O is 6.3 : 4.43 : 1.25 In the simple integer ratio is ( 6.3/1.25) : ( 4.43/1.25) : (1.25/1.25) 5.04 :3.5 : 1

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3 years ago

What mass of iron is formed when 10 grams of carbon react with 80 grams of iron iii oxide?

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Answer:

55.85 grams of Fe is formed.

Explanation:

Identify the reaction:

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Identify the limiting reactant, previously determine the mol of each reactant

(mass / molar mass)

10 g / 12 g/m = 0.83 moles C

80 g / 159.7 g /m = 0.500 moles Fe₂O₃

2 moles of oxide need 3 moles of C, to react

0.5 moles of oxide, will need ( 0.5 . 3)/ 2 = 0.751 mol

I have 0.83 moles of C, so C is the excess.

The limiting is the oxide.

3 mol of C need 2 mol of oxide to react

0.83 mol of C, will need (0.83 . 2)/ 3 = 0.553 mol of oxide, and I only have 0.5 (That's why Fe₂O₃ is the limiting)

Ratio is 2:4 (double)

If I have 0.5 moles of oxide, I will produce the double, in the reaction.

1 mol of Fe, will be produce so its mass is 55.85 g

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3 years ago

A student wants to make a 0.150 M aqueous solution of silver (I) nitrate but only has 11.27 g of AgNO3. What volume of the 0.150

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Answer:

442.3 mL

Explanation:

Remember that Molarity is a measure of concentration in Chemistry and it's defined as the number of moles of the substance divided by liters of the solution:

$M=\frac{Moles of substance X}{Volume of the solution}$

Then, you can express 11.27 g of AgNO3 as moles of AgNO3 using the molar mass of the compound:

$11.27 g AgNO_{3} *\frac{1 mole AgNO_{3}}{169.87 g AgNO_{3}} = 0.06634 moles AgNO_{3}$

Then you can solve for the volume of the solution:

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Hope it helps!

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3 years ago