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aleksandrvk [35]

2 years ago

8

PLEASE HELP WILL GIVE BRAINLIEST How much should be invested now at an interest rate of 5.5% per year, compounded continuously,

to have $3500 in two years?
Do not round any intermediate computations, and round your answer to the nearest cent.

1 answer:

tensa zangetsu [6.8K]2 years ago

3 0

Answer:

find the three intergers inAP such that their sum is 27 and their ptoduct

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A company has a policy of retiring company cars; this policy looks at number of miles driven, purpose of trips, style of car and

vredina [299]

Answer:

2.35%

Step-by-step explanation:

Mean number of months (M) = 39 months

Standard deviation (S) = 10 months

According to the 68-95-99.7 rule, 95% of the data is comprised within two standard deviations of the mean (39-20 to 39+20 months), while 99.7% of the data is comprised within two standard deviations of the mean (39-30 to 39+30 months).

Therefore, the percentage of cars still in service from 59 to 69 months is:

$P_{59\ to\ 69}=\frac{P_{9\ to\ 69}-P_{19\ to\ 59}}{2} \\P_{59\ to\ 69}=\frac{99.7-95}{2}\\P_{59\ to\ 69}=2.35\%$

The approximate percentage of cars that remain in service between 59 and 69 months is 2.35%.

8 0

3 years ago

If f(x) varies directly with x and f(x)=40 when x=8, find the value of f(x) when x=2.

melamori03 [73]

f(x)=40

x=8

so if x=2 it would be 40/8 which is 5

6 0

3 years ago

Read 2 more answers

Help please<br> what is<br>

dsp73

Option A. is correct for the given condition.

Lets solve it through steps of range and functions,

First of all, Solve the equation:
$f(x) = |x|+5$
$= > x = -5$ (1)

$= > x = 5$ (2)

So these would be the ranges of X in between 5 and -5.

Hence option A. $R{f(x)eR [f(x) < 5}$ is correct.

Learn more about range and functions on:

https://brainly.ph/question/10400053

#SPJ10

3 0

2 years ago

Prove or disprove (from i=0 to n) sum([2i]^4) <= (4n)^4. If true use induction, else give the smallest value of n that it doe

ddd [48]

Answer:

The statement is true for every n between 0 and 77 and it is false for $n\geq 78$

Step-by-step explanation:

First, observe that, for n=0 and n=1 the statement is true:

For n=0: $\sum^{n}_{i=0} (2i)^4=0 \leq 0=(4n)^4$

For n=1: $\sum^{n}_{i=0} (2i)^4=16 \leq 256=(4n)^4$

From this point we will assume that $n\geq 2$

As we can see, $\sum^{n}_{i=0} (2i)^4=\sum^{n}_{i=0} 16i^4=16\sum^{n}_{i=0} i^4$ and $(4n)^4=256n^4$ . Then,

$\sum^{n}_{i=0} (2i)^4 \leq(4n)^4 \iff \sum^{n}_{i=0} i^4 \leq 16n^4$

Now, we will use the formula for the sum of the first 4th powers:

$\sum^{n}_{i=0} i^4=\frac{n^5}{5} +\frac{n^4}{2} +\frac{n^3}{3}-\frac{n}{30}=\frac{6n^5+15n^4+10n^3-n}{30}$

Therefore:

$\sum^{n}_{i=0} i^4 \leq 16n^4 \iff \frac{6n^5+15n^4+10n^3-n}{30} \leq 16n^4 \\\\ \iff 6n^5+10n^3-n \leq 465n^4 \iff 465n^4-6n^5-10n^3+n\geq 0$

and, because $n \geq 0$ ,

$465n^4-6n^5-10n^3+n\geq 0 \iff n(465n^3-6n^4-10n^2+1)\geq 0 \\\iff 465n^3-6n^4-10n^2+1\geq 0 \iff 465n^3-6n^4-10n^2\geq -1\\\iff n^2(465n-6n^2-10)\geq -1$

Observe that, because $n \geq 2$ and is an integer,

$n^2(465n-6n^2-10)\geq -1 \iff 465n-6n^2-10 \geq 0 \iff n(465-6n) \geq 10\\\iff 465-6n \geq 0 \iff n \leq \frac{465}{6}=\frac{155}{2}=77.5$

In concusion, the statement is true if and only if n is a non negative integer such that $n\leq 77$

So, 78 is the smallest value of n that does not satisfy the inequality.

Note: If you compute $(4n)^4- \sum^{n}_{i=0} (2i)^4$ for 77 and 78 you will obtain:

$(4n)^4- \sum^{n}_{i=0} (2i)^4=53810064$

$(4n)^4- \sum^{n}_{i=0} (2i)^4=-61754992$

7 0

3 years ago

The high temperature one day was 30°F. Then

expeople1 [14]

Yes because when you subtract a number, you can also say that you added a negative. So if it dropped 23 degrees, then you also added -23 degrees

5 0

3 years ago