Question

Math Help Part 1 (Please Help)

Answer 1

Answer:

$EY=56$

$DW=70$

$ZE=53$

Step-by-step explanation:

$YW \ \textsf{is the bisector of }EF \implies FW=EW=70\\\\EY =\sqrt{EW^2-YW^2}=\sqrt{70^2-42^2}=56$

$XW \ \textsf{is the bisector of } DF \implies DW=FW=70$

$ZW \ \textsf{is the bisector of }DE \implies ZE = \dfrac12DE\\\\DE=106 \implies ZE = \dfrac{106}{2}=53$