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Yuki888 [10]
3 years ago
11

The general equation for depreciation is given by y = A(1 – r)t, where y = current value, A = original cost, r = rate of depreci

ation, and t = time, in years. A car was purchased 6 years ago for $25,000. If the annual depreciation rate is 11%, which equation can be used to determine the approximate current value of the car?
Mathematics
1 answer:
Lesechka [4]3 years ago
4 0

Answer:

y=25,000(0.89)^6

Step-by-step explanation:

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Graph a line with a slope of 4 that contains the point (3,0).
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just graph the line: y=4x-12

Step-by-step explanation:

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Find the slope<br> A- 1/4<br> B- 1/3<br> C- 1/5<br> D- 2/3
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1/3

Step-by-step explanation:

if you move up 1 over three, the line intersects the graph

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In the diagram below, m
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m<CGE: 86

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There are 3 rivers and after each river lies a grave. So there are 3 rivers and 3 graves. A man wants to leave the SAME amount o
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a road follows the shape of a parabola f(x)=3x2– 24x + 39. A road that follows the function g(x) = 3x – 15 must cross the stream
Nonamiya [84]

the coordinates where the bridges must be built is (3,-6) and (6,3) .

<u>Step-by-step explanation:</u>

Here we have , a road follows the shape of a parabola f(x)=3x2– 24x + 39. A road that follows the function g(x) = 3x – 15 must cross the stream at point A and then again at point B. Bridges must be built at those points.We need to find Identify the coordinates where the bridges must be built. Let's find out:

Basically we need to find values of x for which f(x) = g(x) :

⇒ f(x)-g(x)=0

⇒ 3x^2- 24x + 39-(3x - 15 ) =0

⇒ 3x^2- 24x + 39-3x + 15  =0

⇒ 3x^2- 27x + 54  =0

⇒ x^2- 9x + 18  =0

⇒ x^2- 6x-3x + 18  =0

⇒ x(x- 6)-3(x - 6)  =0

⇒ (x-3)(x- 6)  =0

⇒ x=3 , x=6

Value of g(x) at x = 3 : y=3x -15 = 3(3)-15 = -6

Value of g(x) at x = 6 : y=3x -15 = 3(6)-15 = 3

Therefore , the coordinates where the bridges must be built is (3,-6) and (6,3) .

7 0
3 years ago
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