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3 years ago

1 - 500 principal earning 4% compounded quarterly, after 6 year.

1 answer:

4 0

You'll have <span>$634.87 after 6 years at 4% compounded quarterly, thus B:
You'll have </span><span>$3,619.80 after 6 months at 6.75% compounded monthly, thus A:

</span>Formulas where n = 1 (compounded once per period or unit t)
1. Calculate Accrued Amount (Principal + Interest) A = P(1 + r)^t
2. Calculate Principal Amount, solve for P. P = A / (1 + r)^t
4. Calculate the rate of interest in decimal, solve for r. r = (A/P)1/(^t - 1)
5. Calculate rate of interest in percent. ...Calculate time, solve for t.

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What’s 12 1/6 converted into a decimal

My name is Ann [436]

Answer:

12.167

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The area of triangle ABC is 3√2 square inches. Find the measure of the acute angle, A, if b = 9 meters and c = 2 meters.

taurus [48]

Answer:

$A\approx 28^{\circ}$

Step-by-step explanation:

Please find the attachment.

We have been given that area of triangle ABC is 3√2 square inches.

$\text{Area}=\frac{1}{2}\text{Base}\times \text{height}$

We know that area of triangle an be found using trigonometry as:

$\text{Area}=\frac{1}{2}\times c\times h$

$\text{sin}(A)=\frac{h}{9}\\h=9\cdot \text{sin}(A)$

$3\sqrt{2}=\frac{1}{2}\times 2\times 9\cdot \text{sin}(A)$

$3\sqrt{2}=9\cdot \text{sin}(A)$

$9\cdot \text{sin}(A)=3\sqrt{2}$

$\text{sin}(A)=\frac{3\sqrt{2}}{9}$

$\text{sin}(A)=\frac{\sqrt{2}}{3}$

Now, we will use inverse sine to find the value of angle A as:

$A=\text{sin}^{-1}(\frac{\sqrt{2}}{3})$

$A=28.1255057^{\circ}$

$A\approx 28^{\circ}$

Therefore, the measure of angle A is approximately 28 degrees.

3 0

3 years ago

Sara has 4\frac{3}{4}4 4 3 yards of red fleece and 2\frac{2}{3}2 3 2 yards of blue fleece fabric. How many yards of red and

Musya8 [376]

Answer:

4567

Step-by-step explanation:

5 0

3 years ago

Find the missing measurement for each figure.

earnstyle [38]

To find h, divide the area by the base:

h = 2442 / 12 = 203.5 km.

6 0

3 years ago

Prove Forall x elementof Z, x^2 - 5x - 1 is odd.

Diano4ka-milaya [45]

Answer with Step-by-step explanation:

Let Z be a set of integers

We have to prove that $x^2-5x-1$ is odd for all value of x $\in$ Z.

There are two cases

1.When x is an odd integer number

2.when x is even integer number

1.When x is an odd integer number

When x is positive odd integer

Then $x^2$ is positive odd number (because square of odd positive number is always positive an odd number )

5x is also odd number

-5x -1 = -even number

Suppose x=3

Then -15-1=-16

Odd number - even number=Odd number

Hence , $x^2-5x-1$ is an odd number .

When x is negative odd number

Then x square is positive odd number and 5x is negative odd term term

Therefore,odd number + odd number -1=Even number -1=Odd number

Hence $x^2-5x-1$ is an odd number.

2.When x is an even number

When x is positive even number

x square is positive even number and 5x is positive even number

Even number -Even number -1 =Even number -odd number =Odd number

Suppose x=4

$x^2-5x-1$ =16-20-1=-5=Odd number

When x is negative even number

Then x square is positive even number and 5x is negative even number

$x^2-5x-1$ =Even number +Even number -1=Even number -1=Odd number

Hence, for all elements of Z $x^2-5x-1$ is odd.

7 0

3 years ago