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pickupchik [31]
3 years ago
14

a direct variation function contains the points ( -8, -6 ) and (12,9 ) . Which equation represents the function ?

Mathematics
1 answer:
9966 [12]3 years ago
8 0

Answer:

y = \frac{3}{4} x

Step-by-step explanation:

Given that the quantities vary directly then the equation relating them is

y = kx ← k is the constant of variation

To find k use either of the 2 given points

Using (12, 9), that is x = 12 when y = 9, then

k = \frac{y}{x} = \frac{9}{12} = \frac{3}{4}

y = \frac{3}{4} x ← equation of variation

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Solve the system of equations by using substitution.<br> x+8y=-2<br> x-3y=20
zysi [14]

Answer:

(14, -2)

Step-by-step explanation:

To solve by using substitution, begin by solving for a variable in the first equation. Let's solve for x:

x+8y=-2\\x=-2-8y

Now we know what <em>x</em> equals. Let's substitute this into the second equation:

x-3y=20\\(-2-8y)-3y=20

We can then simplify:

-2-8y-3y=20 Given equation

-2-11y=20 Combine y terms

-11y=22 Add 2

y=-2 Divide by -11

So, we now know the value of y = -2.

To find the value of X, we can substitute the value of Y into one of the equations. Let's use the first one:

x+8y=-2

x+8(-2)=-2 Substitute for y

x-16=-2 Distribute 8

x=14 Add 16

So, we now know the value of x = 14.

Therefore, we know a solution to the system of equations is (14, -2).

4 0
3 years ago
What is the volume of a sphere with a radius of 7 cm? Sphere V = 4 3 πr3 1. Substitute the radius into the formula:    V = 4 3 π
netineya [11]

Answer:

1436.75504 or 1372/3π cm^3

Step-by-step explanation:

The volume of a sphere can be found using:

V = 4/3 πr^3

We know the radius is 7, so we can substitute 7 in for r

V = 4/3 π7^3

Evaluate the exponent

V = 4/3 π 343

If we want the answer in terms of pi, multiply the two other numbers, that are not pi: 4/3 and 343.

v= (4/3*343)π

v=1372/3π

If we want an exact answer, multiply 1372/3 and pi

v=1436.75504

So, the volume is 1436.75504 or 1372/3 π cm^3

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3 years ago
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inysia [295]

Answer:

(x+3)^2+(y-2)^2=9

Step-by-step explanation:

<u>Equation of a circle</u>

(x-a)^2+(y-b)^2=r^2

where:

  • (a, b) is the center
  • r is the radius

From inspection of the diagram, the center of the circle <em>appears</em> to be at point (-3, 2), although this is not very clear.  Therefore, a = -3  and  b = 2.

Substitute these values into the general form of the equation of a circle:

\implies (x-(-3))^2+(y-2)^2=r^2

\implies (x+3)^2+(y-2)^2=r^2

Again, from inspection of the diagram, the <u>maximum vertical point</u> of the circle appears to be at y = 5.  Therefore, to calculate the radius, subtract the y-value of the center point from the y-value of the maximum vertical point:

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Substitute the found value of r into the equation:

\implies (x+3)^2+(y-2)^2=3^2

Therefore, the final equation of the given circle is:

\implies (x+3)^2+(y-2)^2=9

7 0
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Nataly_w [17]

Answer:

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Step-by-step explanation:

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ahrayia [7]
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3 years ago
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