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3 years ago

When forming a bond, an atom that has 3 electrons in its second shell and a filled first shell will?

1 answer:

7 0

Macromolecule polymers are assembled by the connecting of monomers. An -OH group is detached from one monomer and a hydrogen atom is detached from an additional in a procedure named dehydration synthesis in the monomers bond. For every subunit supplementary to a macromolecule in which one water molecule is detached. Macromolecule polymers are broken down by breaking bonds among subunits. This procedure is named hydrolysis and is the opposite of dehydration. During hydrolysis the hydrogen atom is supplementary to one monomer and a hydroxyl cluster to the other and by breaking the covalent bond in the middle of the monomers.

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Would a decrease in force cause a decrease in pressure

natta225 [31]

IdkAnswer:

Explanation:

4 0

4 years ago

The pupil of a cat's eye narrows to a slit width of 0.5 mm in daylight. What is the angular resolution of the cat's eye in dayli

Elenna [48]

Answer:

C. 10⁻³ rads

Explanation:

Here, we shall use Rayleigh's Criterion to find out the angular resolution of Cat's eye during day light. Rayleigh's Criterion is written as follows:

θ = λ/a

where,

θ = angular resolution of Cat's eye = ?

λ = wavelength = 500 nm = 5 x 10⁻⁷ m

a = slit width of eye = 0.5 mm = 5 x 10⁻⁴ m

Therefore,

θ = (5 x 10⁻⁷ m/5 x 10⁻⁴ m)

Therefore,

θ = 0.001

θ = Sin⁻¹(0.001)

θ = 0.001 rad = 1 x 10⁻³ rad

Hence, the correct answer is:

C. 10⁻³ rads

4 0

3 years ago

21% of the atmosphere a:Nitrogen B:Oxygen C:CO^2 D:Argon

Vilka [71]

21% of the atmosphere is Oxygen.

4 0

4 years ago

If a wave's third harmonic has a frequency of 24 Hz, what is its

Charra [1.4K]

Answer:

8 Hz, 48 Hz

Explanation:

The standing waves on a string (or inside a pipe, for instance) have different modes of vibrations, depending on how many segments of the string are vibrating.

The fundamental frequency of a standing wave is the frequency of the fundamental mode of vibration; then, the higher modes of vibration are called harmonics. The frequency of the n-th harmonic is given by

$f_n = nf_1$

where

$f_1$ is the fundamental frequency

In this problem, we know that the wave's third harmonic has a frequency of

$f_3=24 Hz$

This means this is the frequency for n = 3. Therefore, we can find the fundamental frequency as:

$f_1=\frac{f_3}{3}=\frac{24}{3}=8 Hz$

Now we can also find the frequency of the 6-th harmonic using n = 6:

$f_6 = 6 f_1 = 6 (8)=48 Hz$

6 0

3 years ago

A 62-kg person jumps from a window to a fire net 20.0 m directly below, which stretches the net 1.4 m. Assume that the net behav

gayaneshka [121]

Answer:

a) x = 0.098

b) x = 2.72 m

Explanation:

(a) To find the stretch of the fire net when the same person is lying in it, you can assume that the net is like a spring with constant spring k. It is necessary to find k.

When the person is falling down he acquires a kinetic energy K, this energy is equal to the elastic potential energy of the net when it is max stretched.

Then, you have:

$K=U\\\\\frac{1}{2}mv^2=\frac{1}{2}kx^2$ (1)