Answer:
25 meters
Explanation:
1 sec is 2.5, 1x10 so 2.5x10=25
Sum the forces in the y (upward) direction
Applying the kinematic equations of linear motion we have that the displacement as a function of the initial speed, acceleration and time is
Again through the kinematic equation of linear motion that describes velocity as the change of displacement in a given time, we have to
Therefore the horizontal distance between the target and the rocket should be 38.83m
Answer:
Hi.Thank you for the points.