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Zinaida [17]
2 years ago
12

Blayne wants to kill the biggest buck in Allen County this year. Design an experiment to increase his chances of tagging that bu

ck!
Identify the independent variable, dependent variable, and controlled variables in his experiment.
Physics
1 answer:
zheka24 [161]2 years ago
3 0

Answer:

if k k of it if it or it or j3 it

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Jonah observes the Sun through a special filtered telescope during a total solar eclipse. He sees a red ring and a faint white r
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The answer would be C. chromosphere and corona.

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Which statement describes the speed of electromagnetic waves?
goldfiish [28.3K]

Answer:

Their speed in a vacuum is a constant value.

Explanation:

Electromagnetic waves consits of oscillations of electric field and magnetic field. The oscillations of these fields occur in a direction perpendicular to the direction of propagation of the waves, so they are transverse wave. Electromagnetic waves, contrary to mechanical waves, do not need a medium to propagate, so they can also travel through a vacuum. In a vacuum, their speed is constant and has always the same value, the speed of light:

c=3\cdot 10^8 m/s

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When the same masses are heated by the same amount, which of the following substances will heat up the slowest?
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What is nuclear fission? (Points : 1)
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The splitting of the atomic nucleus into parts
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3 years ago
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A car horn emits a frequency of 400 Hz. A car traveling at 20.0 m/s sounds the horn as it approaches a stationary pedestrian. Wh
Temka [501]

Answer:

The observed frequency by the pedestrian is 424 Hz.

Explanation:

Given;

frequency of the source, Fs = 400 Hz

speed of the car as it approaches the stationary observer, Vs = 20 m/s

Based on Doppler effect, as the car the approaches the stationary observer, the observed frequency will be higher than the transmitted (source) frequency because of decrease in distance between the car and the observer.

The observed frequency is calculated as;

F_s = F_o [\frac{v}{v_s + v} ] \\\\

where;

F₀ is the observed frequency

v is the speed of sound in air = 340 m/s

F_s = F_o [\frac{v}{v_s + v} ] \\\\400 = F_o [\frac{340}{20 + 340} ] \\\\400 = F_o (0.9444) \\\\F_o = \frac{400}{0.9444} \\\\F_o = 423.55 \ Hz \\

F₀ ≅ 424 Hz.

Therefore, the observed frequency by the pedestrian is 424 Hz.

8 0
3 years ago
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