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Montano1993 [528]
2 years ago
12

Does everything in a black hole contain a singularity?

Physics
2 answers:
Lapatulllka [165]2 years ago
8 0
In the real universe, no black holes contain singularities. In general, singularities are the non-physical mathematical result of a flawed physical theory.
melamori03 [73]2 years ago
4 0

Answer:

All black holes contain singularities, however not all singularities involve black holes. A neutron star may be dense, matter the size of a pinhead can weigh as much as the earth, but there seems to be a mathematical cut-off point beyond which a black hole is formed.

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(b) Two containers made of insulating material contain the same volume of water at room
masha68 [24]

Answer:

the volume of liquid decreased due to evaporation from the exposed free surface of water so molecules got evaporated .

evaporation occurs at room temperature.

5 0
3 years ago
A piston releases 18 J of heat into its surroundings while expanding from 0.0002 m^3 to 0.0006 m^3 at a constant pressure of 1.0
Elodia [21]

Answer:

value of heat is 18 J

2. step by step

formular w=p(volume1-volume2)

w= 1.0×10^5(0.0006-0.0004)

w= 40 J

8 0
3 years ago
A circular pizza into 3 equal parts, one piece of pizza is taken out. Estimate the degree measure of the single piece of pizza a
seropon [69]

Answer:

A circular pizza has a angle of 360 degrees. When you cut it into 3 equal pieces you divide 360 by 3,you get 120 degrees. And following the conversion of 120 degree into radian you get 2pie/3 radians.

6 0
3 years ago
Read 2 more answers
A far-sighted person has a near-point of 80 cm. To correct their vision so that they can see objects that are as close as 10 cm
bekas [8.4K]

Answer:

f = 8.89 cm

Explanation:

As we know that Far sighted person has near point shifted to 80 cm distance

so he is able to see the object 80 cm

now the distance of lens from eye is 2 cm

and the person want to see the objects at distance 10 cm

so here the image distance from lens is 80 cm and the object distance from lens is 8 cm

now from lens formula we have

\frac{1}{d_i} + \frac{1}{d_0} = \frac{1}{f}

-\frac{1}{80} + \frac{1}{8} = \frac{1}{f}

f = 8.89 cm

3 0
3 years ago
If the average pitcher is releasing the ball from a height of 1.8 m above the ground, and the pitcher's mound is 0.2 m higher th
neonofarm [45]

Answer: A. 2.0m above ground

Explanation:

Height of the pitcher from the floor of his mound = 1.8m

Height of the mound above the rest of the field = 0.2m

Since the height difference between the mound and the ground the catcher stands on = 0.2m and the pitcher throws the ball horizontally, then the catcher has to hold his glove at (1.8 + 0.2)m

above ground.

= 2.0m above ground (option A)

7 0
3 years ago
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