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2 years ago

7

Please help me outtt

1 answer:

balandron [24]2 years ago

3 0

I’d say 74 but not completely sure

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A carpenter has 16 1/2 m of wood. He cuts the wood into pieces that are each 2 3/4 m long. How many pieces of wood does the carp

NNADVOKAT [17]

Simplify the denominator so it is the same
divide the 4 by 2
4 divided by 2=2
now the denominator the same.
16 1/2
2 3/2
multiply 3x1
so far, it is 3/2
it is an improper fraction
divide.
2 divides by 3 = 0.1 i know
1/2
Hope this helped :D! can you mark me brainliest...

5 0

4 years ago

Read 2 more answers

Half (1/2) of the marbles in a bag are red. A third (1/3) are white. The other six (6) are blue. How many marbles are in the bag

NARA [144]

Answer:36 marbles

Step-by-step explanation:1/2*3=3/6

1/3*2=2/6 3/6+2/6=5/6 6 marbles = 1/6 of the bag 6*6=36

7 0

4 years ago

What’s the constant?

anyanavicka [17]

8 would be the constant but in this situation there is a variable next to it so I’m not sure if it would be considered a constant

6 0

3 years ago

Read 2 more answers

Consider the inequality-5(x+7)<-10 write an inequality representing the solution for x

GrogVix [38]

Answer:

<h2>x > -5</h2>

Step-by-step explanation:

-5(x + 7) < -10 <em>use the distributive property </em><em>a(b + c) = ab + ac</em>

(-5)(x) + (-5)(7) < -10

-5x - 35 < -10 <em>add 35 to both sides</em>

-5x < 25 <em>change the signs</em>

5x > - 25 <em>divide both sides by 5</em>

x > -5

6 0

3 years ago

Given f(x)=2x^2+3x-5 for what values of x is f(x) positive

kow [346]

Answer:

The function f(x) is positive in the interval (-≠,-2.5) ∪ (1,∞)

Step-by-step explanation:

we have

$f(x)=2x^{2}+3x-5$

This is a vertical parabola open upward (the leading coefficient is positive)

The vertex is a minimum

The coordinates of the vertex is the point (h,k)

step 1

Find the vertex of the quadratic function

Factor the leading coefficient 2

$f(x)=2(x^{2}+\frac{3}{2}x)-5$

Complete the square

$f(x)=2(x^{2}+\frac{3}{2}x+\frac{9}{16})-5-\frac{9}{8}$

$f(x)=2(x^{2}+\frac{3}{2}x+\frac{9}{16})-\frac{49}{8}$

Rewrite as perfect squares

$f(x)=2(x+\frac{3}{4})^{2}-\frac{49}{8}$

The vertex is the point (-\frac{3}{4},-\frac{49}{8})

step 2

Find the x-intercepts (values of x when the value of f(x) is equal to zero)

For f(x)=0

$2(x+\frac{3}{4})^{2}-\frac{49}{8}=0$

$2(x+\frac{3}{4})^{2}=\frac{49}{8}$

$(x+\frac{3}{4})^{2}=\frac{49}{16}$

take the square root both sides

$x+\frac{3}{4}=\pm\frac{7}{4}$

$x=-\frac{3}{4}\pm\frac{7}{4}$

$x_1=-\frac{3}{4}+\frac{7}{4}=1$

$x_2=-\frac{3}{4}-\frac{7}{4}=-2.5$

therefore

The function f(x) is negative in the interval (-2.5,1)

The function f(x) is positive in the interval (-≠,-2.5) ∪ (1,∞)

see the attached figure to better understand the problem

6 0

4 years ago