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Mars2501 [29]
2 years ago
14

Free p0ints! Come and get em

Chemistry
1 answer:
Aleonysh [2.5K]2 years ago
7 0
Thank you!! I appreciate it. Have a wonderful day!
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Nitrogen dioxide is one of the many oxides of nitrogen (often collectively called "NOx") that are of interest to atmospheric che
Helga [31]

Answer:

Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time is 0.82 atm.

Explanation:

2NO_2(g)\rightleftharpoons N_2O_4(g)

Initially

3.0 atm                 0

At equilibrium

(3.0-2p)                 p

Equilibrium partial pressure of NO_2=2.1atm=3.0-2p

p = 0.45 atm

The value of equilibrium constant wil be given by :

K_p=\frac{p_{N_2O_4}}{(p_{NO_2})^2}=\frac{p}{(3.0-2p)^2}

K_p=\frac{0.45}{(2.1)^2}=0.10

After addition of 1.5 atm of nitrogen dioxide gas equilibrium reestablishes it self :

2NO_2(g)\rightleftharpoons N_2O_4(g)

After adding 1.5 atm of NO_2:

(2.1+1.5) atm                0.45 atm

At second equilibrium:'

(3.6-2P)                     (0.45+P)

The expression of equilibrium can be written as:

K_p=\frac{p'_{N_2O_4}}{(p'_{NO_2})^2}

0.10=\frac{(0.45+P)}{(3.6-2P)^2}

Solving for P:

P = 0.37 atm

Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time:

= (0.45+P) atm = (0.45 + 0.37 )atm = 0.82 atm

Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time is 0.82 atm.

5 0
3 years ago
6. You have $50.00. You buy a CD for $15.50. You sell it to your friend for $12.00. He doesn't
kompoz [17]

Answer: the answer is that you made $2

Explanation:

4 0
3 years ago
A 1500 L weather balloon is at 'a temperature of 290 K on the ground. As it rises the
myrzilka [38]

Answer:

1086.2 L

Explanation:

The computation of the volume of the elevation is given below:

Here we assume the volume of the elevation be x

As we know that

V¹ ÷ T¹ = V² ÷ T²

Here

V^1 = 1500

T^1 = 290

V^2 = x

T^2 = 210

Now place these values to the above formula

So,  

1500 ÷ 290 = x ÷ 210

x = 1086.2 L

7 0
3 years ago
How many grams of hydrogen are in "69" g of ch4o?
nasty-shy [4]

Answer:

             8.62 g of Hydrogen

Solution:

Molar mass of CH₄O (Methanol) is 32 g.mol⁻¹.

It means,

                  32 g of CH₄O contains  =  4 g of Hydrogen

Then,

             69 g of CH₄O will contain  =  X g of Hydrogen

Solving for X,

                    X  =  (69 g × 4 g) ÷ 32 g

                    X  =  8.62 g of Hydrogen

6 0
3 years ago
Sodium pentothal is a short-acting barbiturate derivative used as a general anesthetic and known in popular culture as truth ser
exis [7]

Answer:

Figure 1

Explanation:

In this case, we have to ester with a <u>"malonic synthesis"</u> in which we have to add a strong (ethoxide) to produce an enolate ion that would form a new C-C bond with an alkyl halide (ethyl bromide and bromo pentane). Then a <u>"nucleophilic acyl substitution reaction"</u> takes place to add thiourea, in this step two ethanol groups are eliminated to form a cyclic structure. Finally, an "<u>elimination reaction"</u> happen by the addition of sodium hydroxide generating a double bond and a negative charge in the sulfur atom that is neutralized with the positive charge of sodium.

See figure 1 for the total mechanism

I hope it helps!

4 0
3 years ago
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