Answer:
Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time is 0.82 atm.
Explanation:
Initially
3.0 atm 0
At equilibrium
(3.0-2p) p
Equilibrium partial pressure of 
p = 0.45 atm
The value of equilibrium constant wil be given by :
After addition of 1.5 atm of nitrogen dioxide gas equilibrium reestablishes it self :
After adding 1.5 atm of 
:
(2.1+1.5) atm 0.45 atm
At second equilibrium:'
(3.6-2P) (0.45+P)
The expression of equilibrium can be written as:
Solving for P:
P = 0.37 atm
Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time:
= (0.45+P) atm = (0.45 + 0.37 )atm = 0.82 atm
Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time is 0.82 atm.
Answer: the answer is that you made $2
Explanation:
Answer:
1086.2 L
Explanation:
The computation of the volume of the elevation is given below:
Here we assume the volume of the elevation be x
As we know that
V¹ ÷ T¹ = V² ÷ T²
Here
V^1 = 1500
T^1 = 290
V^2 = x
T^2 = 210
Now place these values to the above formula
So,
1500 ÷ 290 = x ÷ 210
x = 1086.2 L
Answer:
8.62 g of Hydrogen
Solution:
Molar mass of CH₄O (Methanol) is 32 g.mol⁻¹.
It means,
32 g of CH₄O contains = 4 g of Hydrogen
Then,
69 g of CH₄O will contain = X g of Hydrogen
Solving for X,
X = (69 g × 4 g) ÷ 32 g
X = 8.62 g of Hydrogen
Answer:
Figure 1
Explanation:
In this case, we have to ester with a <u>"malonic synthesis"</u> in which we have to add a strong (ethoxide) to produce an enolate ion that would form a new C-C bond with an alkyl halide (ethyl bromide and bromo pentane). Then a <u>"nucleophilic acyl substitution reaction"</u> takes place to add thiourea, in this step two ethanol groups are eliminated to form a cyclic structure. Finally, an "<u>elimination reaction"</u> happen by the addition of sodium hydroxide generating a double bond and a negative charge in the sulfur atom that is neutralized with the positive charge of sodium.
See figure 1 for the total mechanism
I hope it helps!
