Answer:
d. 0.208 M NaOH
Explanation:
M[NaOH] = 23+16+1= 40g/mol
2.40L = 2.4dm3
M=m/Mv
M=20.0g/40g/mol×2.4dm3
M=20.0g ÷ 96
M= 0.208 M NaOH
Moles of electrons:
The moles of electrons that are transferred are 12F
A balanced equation:
2 moles of Aluminium metal react with excess copper(II) nitrate.
![2Al + 3Cu{(NO_3)}_2 \rightarrow 2Al{(NO_3)}_3 +3 Cu](https://tex.z-dn.net/?f=2Al%20%2B%203Cu%7B%28NO_3%29%7D_2%20%20%5Crightarrow%202Al%7B%28NO_3%29%7D_3%20%2B3%20Cu)
Given:
Moles of Aluminium = 2
As Aluminium goes from 0 to +3 oxidation state
![Al \rightarrow Al^{3+} + 3e^-](https://tex.z-dn.net/?f=Al%20%5Crightarrow%20Al%5E%7B3%2B%7D%20%2B%203e%5E-)
And copper goes from +2 to 0
![Cu^{2+} + 2e^-\rightarrow Cu](https://tex.z-dn.net/?f=Cu%5E%7B2%2B%7D%20%2B%202e%5E-%5Crightarrow%20Cu)
On balancing the number of electrons we get:
For 1 mole of Al
is required.
Therefore for 2 moles of Al,
Total
F mole of electrons
Where F= Faraday's constant= 96500 C
So, 12F moles of electrons are transferred.
Learn more about Faraday's Law here,
brainly.com/question/27985929
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O2 is an example of a molecule
The magnitude of a star as it would appear to a hypothetical observer at a distance of 10 parsecs or 32.6 light-years. This rates how visible celestial bodies are when they are all viewed from the same distance. Luminosity: The brightness of a star in comparison with that of the sun.
They both build up to form electricity