Answer:
75%
Step-by-step explanation:
20-5=15 - change in numbers
15/20×100%= 75%
-3x + 4y = 12
x - y = 1....x = y + 1
-3(y + 1) + 4y = 12
-3y - 3 + 4y = 12
-3y + 4y = 12 + 3
y = 15
x - y = 1
x - 15 = 1
x = 1 + 15
x = 16
one solution (16,15)
Answer:
0.6
Step-by-step explanation:
0.6 is extremely high
Answer:
Player II should remove 14 coins from the heap of size 22.
Step-by-step explanation:
To properly answer this this question, we need to understand the principle and what it is exactly is being asked.
This question revolves round a game of Nim
What is a game of Nim: This is a strategic mathematical game whereby, two opposing sides or opponent take turns taking away objects from a load or piles. On each turn, a player remove at least an object and may remove any number of objects provided they all come from the same heap/pile.
Now, referring back to the question, we should first understand that:
22₂ = 1 0 1 1 0
19₂= 1 0 0 1 1
14₂= 0 1 1 1 0
11₂= 0 1 0 1 1
and also that the “bit sums” are all even, so this is a balanced game.
However, after Player I removes 6 coins from the heap of size 19, Player II should remove 14 coins from the heap of size 22.
