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vichka [17]
2 years ago
10

The cost of 7 chairs and 2 tables is equal.If the cost of 6 chairs and 5 tables is 10575, find the cost of 12 chairs.​

Mathematics
1 answer:
Igoryamba2 years ago
7 0

Answer:

5400

Step-by-step explanation:

Let x represent the cost of a chair and y represent the cost of a table. We can use this to set up a system of equations:

7x=2y

6x+5y=10575

We can solve this system using substitution.

Start by rewriting the first equation in terms of x.

7x=2y\\\text{Divide both sides by 7}\\x=\frac{2}{7}y

Substitute this into the second equation:

6(\frac{2}{7}y)+5y=10575\\\frac{12}{7}y+5y+10575\\\frac{12}{7}y+\frac{35}{7}y=10575\\\frac{47}{7}y=10575

Multiply both sides by 7

47y=74025

Divide both sides by 47

y=1575

This means...

7x=2(1575)\\7x=3150

Divide both sides by 7

x=450

One chair costs 450. Now, multiply this number by 12 to find the cost of 12 chairs.

450*12=5400

12 chairs cost 5400.

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<h3>Answers:</h3>
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Explanation:

a)

MR = 24 is given. Note the single tickmark on this segment. The other segment HR has the same tickmark, so it is the same length as MR.

HR = MR = 24

-----------------

b)

The double tickmarks tell us TR and RA are the same length. They combine to form segment AT. So this means segment AT is cut in half to get TR and RA.

TR = (1/2)*(AT)

2*TR = AT.... multiply both sides by 2

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c)

MH is cut in half at point R for similar reasoning as part b)

Put another way, MH is twice as long as MR.

MH = 2*MR

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2*MR = 58

MR = 58/2

MR = 29

-------------------

d)

R is the midpoint of segment MH because R cuts MH in half. Point R bisects MH.

R is also the midpoint of AT for similar reasoning. It's all based on the tickmarks telling us which segments are congruent to one another.

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