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Rainbow [258]
3 years ago
15

A swimming pool is shaped like a right rectangular prism with length 20 feet, height 8 feet, and width 15 feet. If the pool's wa

ter line is one foot below the top of the pool, find the volume of water in the pool.D) 10.5 square units
Mathematics
2 answers:
umka21 [38]3 years ago
6 0

Answer:

2100

hope this helps :)

Dimas [21]3 years ago
4 0

Answer:

Volume of water in the pool= 2100 feet^3

Step-by-step explanation:

The swimming pool have dimensions;

Length= 20 feet\\Width= 15 feet\\Height= 8 feet

We have to find the volume of water in the pool which is one foot below the top of pool.

So,Height of water in the pool= 8-1= 7 feet

Volume of the water in the pool:

                                  = length *width*height\\                                                     = 20*15*7\\                                                       =2100 cubic feet

Volume of water in the pool= 2100 feet^3

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muminat

Answer:

5(x + 3) = 3x - 4

=> (5 * x ) + (5 * 3) = 3x - 4

=> 5x + 15 = 3x - 4

=> 5x = 3x - 4 - 15

=> 5x - 3x = -4 - 15

=> 2x = -19

=> x = -19/2

=> x = -9.5

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sergejj [24]
1) x + 2xyz
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Let us assume that x = 3; y = 2; z = 1 and we disregard the coefficients
1) x + 2xyz  ⇒ 3 + (3)(2)(1) = 9
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3 years ago
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What is 138÷12 to the nearest cent
Ray Of Light [21]

Answer:

$11.50

Step-by-step explanation:

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6 0
3 years ago
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Plz help meee thanks
RoseWind [281]

Answer:

Step-by-step explanation:

Ok, I’ve answered this questioned in a task of mine before, I believe it’s this here we go:

It should be 20 degrees is more than or equal to -60 degrees because the question is asking the relation BETWEEN the two and it has to be an inequality so yea!

I’m in 7th grade I KNOW YOUR PAIN!!!

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3 years ago
Expand the binomial<br> <img src="https://tex.z-dn.net/?f=%28x-%5Cfrac%7B2%7D%7B5%7D%29%5E%7B2%7D" id="TexFormula1" title="(x-\f
kkurt [141]

Answer:

(x- \frac{2}{5})^{2} = x^2 -\frac{4}{5}x + \frac{4}{25}

Step-by-step explanation:

You have two methods to expand this binomial.

Method 1  

If you have the expression:

(x- \frac{2}{5})^{2}

You can write the expression it in the following way:

(x-\frac{2}{5})^{2}=(x-\frac{2}{5})(x-\frac{2}{5})

Then, apply the distributive property:

(x-\frac{2}{5})(x-\frac{2}{5}) = x^2 -\frac{2}{5}x -\frac{2}{5}x+ (\frac{2}{5})\frac{2}{5}

Simplify the expression:

(x-\frac{2}{5})^2= x^2 -\frac{4}{5}x+ (\frac{4}{25})

---------------------------------------------------------------------------------------

Method 2

For any expression of the form:

(a-b)^2

Its expanded form will be:

(a-b)^2= a^2 -2ab + b^2

If

a = x

b =\frac{2}{5}

(x- \frac{2}{5})^{2} = x^2 - 2x\frac{2}{5} + (\frac{2}{5})^2

(x- \frac{2}{5})^{2} = x^2 -\frac{4}{5}x + \frac{4}{25}

3 0
3 years ago
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